Answer and explanation:
A) An ideal fuel must:
- easy to transport and storage.
- have a high calorific value.
B) The <em>calorific value</em> for a fuel is the amount of heat - measured in Joules- which is produced during the complete combustion of the fuel. It is expressed in Joules per Kg of fuel (J/kg).
C) From the data:
mass of fuel = 2 kg
heat produced = 48,000 KJ
We calculate the calorific value by dividing the heat produced by the mass of fuel, as follows:
calorific value = heat produced/mass of fuel = (48,000 KJ)/(2 kg)= 24,000 kJ/kg
Since 1 KJ= 1000 J, we can express the calorific value in J/kg as follows:
24,000 kJ/kg x 1000 J/1 kJ = 2.4 x 10⁷ J/kg
Answer:
solvent (such as water, oil or isopropyl alcohol) is allowed to absorb up the paper strip. ... Different molecules run up the paper at different rates. As a result, components of the solution separate and, in this case, become visible as strips of color on the chromatography paper.
Explanation:
Hope this helps leave a heart c:
The NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.
A spectroscopic method for observing the local magnetic fields surrounding atomic nuclei seems to be nuclear magnetic resonance spectroscopy, also referred to as magnetic resonance spectroscopy as well as NMR spectroscopy.
The identification and study of organic molecules benefit greatly from nuclear magnetic resonance (NMR) spectroscopy. This type of spectroscopy has a straightforward underlying theory. Numerous atom types' nuclei behave like small magnets and frequently align themselves in magnetic fields.
Therefore, the NMR spectroscopy will be used for distinguishing a sample of 1,2-dichloropropane from 1,2-dibromopropane.
To know more about spectroscopy
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I would definitely say that's false.
hope this helps you!:-)
