Answer:
Volume of NaOH required = 3.61 L
Explanation:
H2SO3 is a diprotic acid i.e. it will have two dissociation constants given as follows:
--------(1)
where, Ka1 = 1.5 x 10–2 or pKa1 = 1.824
--------(2)
where, Ka2 = 1.0 x 10–7 or pKa2 = 7.000
The required pH = 6.247 which is beyond the first equivalence point but within the second equivalence point.
Step 1:
Based on equation(1), at the first eq point:
moles of H2SO3 = moles of NaOH
Step 2:
For the second equivalence point setup an ICE table:
Initial 1.98 ? 0
Change -x -x x
Equil 1.98-x ?-x x
Here, ?-x =0 i.e. amount of OH- = x
Based on the Henderson buffer equation:
![pH = pKa2 + log\frac{[SO3]^{2-} }{[HSO3]^{-} } \\6.247 = 7.00 + log\frac{x}{(1.98-x)} \\x=0.634 moles](https://tex.z-dn.net/?f=pH%20%3D%20pKa2%20%2B%20log%5Cfrac%7B%5BSO3%5D%5E%7B2-%7D%20%7D%7B%5BHSO3%5D%5E%7B-%7D%20%7D%20%5C%5C6.247%20%3D%207.00%20%2B%20log%5Cfrac%7Bx%7D%7B%281.98-x%29%7D%20%5C%5Cx%3D0.634%20moles)
Volume of NaOH required is:
Step 3:
Total volume of NaOH required = 3.22+0.389 =3.61 L
Answer:
CARBON HYDROGEN NYTROGEN OXYGEN
Explanation:
POGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOG
The moles of oxygen required to burn Butane is 6 moles.
<h3>What is a Combustion Reaction?</h3>
A reaction in which fuel gets oxidised by an oxidising agent producing a large amount of heat is called a combustion reaction.
In this question
Butane is burnt with oxygen
Molar mass of C₄H₁₀ = (12.0×4 + 1.0×10) g/mol = 58.0 g/mol
Molar mass of O₂ = 16.0×2 g/mol = 32.0 g/mol
Balanced equation for the reaction:
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
Mole ratio C₄H₁₀ : O₂ = 2 : 13
The given mass = 54grams
moles = 54/58 = 0.93 moles
The mole of oxygen required =
0.93/ x = 2/13
0.93*13/2 = x
x = 6.045 moles
Therefore 6 moles of oxygen are required to burn Butane.
To know more about Combustion Reaction
brainly.com/question/12172040
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Your body's skeletal system serves as a support structure. It is responsible for giving the body its structure, allowing mobility, producing blood cells, protecting organs, and storing minerals. The musculoskeletal system is another name for the skeletal system.
(35/18.02)(6.02kJ)=11.6926 kiloJoules
