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motikmotik
3 years ago
5

PLS I NEED HELP ASAP! BRAINLIEST TO FULL ANSWER!!

Chemistry
2 answers:
Serggg [28]3 years ago
7 0

Answer:

CARBON HYDROGEN NYTROGEN OXYGEN

Explanation:

POGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOGPOG

gavmur [86]3 years ago
3 0
Carbon, hydrogen, nitrogen, oxygen
Carbon7 hydrogen8 nitrogen4 oxygen2
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Which one of the following is most likely to lose electrons when forming an ion?
otez555 [7]

Answer:

Option A) Na

Explanation:

From the options given above, sodium (Na) is most likely to lose electron to form ion

Na is a group 1 metal. Metals form ions by losing electron(s).

From the options given above, only Na is a metal and so it is most likely to form ion by losing electron

7 0
3 years ago
9 moles of Ammonia (NH3) are added to 50 L of H2O at a temperature of 29°C. The vapor pressure of water alone is 29.96 mmHg at 2
Westkost [7]

Answer:  The vapor pressure of the solution at 29^0C is 29.86 mm Hg

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\frac{p^o-p_s}{p^o}=i\times x_2

where,

\frac{p^o-p_s}{p^o}= relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

x_2 = mole fraction of solute  

=\frac{\text {moles of solute}}{\text {total moles}}

Given : 9 moles of NH_3 are dissolved in 50 L or 50000 ml of water

mass of water = density\times volume = 1g/ml\times 50000ml=50000g  

moles of solvent (water) = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{50000g}{18g/mol}=2778moles

Total moles = moles of solute  + moles of solvent = 9 mol + 2778 mol = 2787  

x_2 = mole fraction of solute  

=\frac{9}{2787}=3.2\times 10^{-3}

\frac{29.96-p_s}{29.96}=1\times 3.2\times 10^{-3}

p_s=29.86mmHg

Thus the vapor pressure of the solution at 29^0C is 29.86 mm Hg

5 0
3 years ago
The first two columns in the periodic table react with? <br><br> A) Gases<br> B) Metals<br> C) Water
timofeeve [1]
It should be A because the periodic table starts with Hydrogen in this one is a gas
8 0
3 years ago
Read 2 more answers
Calculate the energy required to heat 1.30kg of water from 22.4°C to 34.2°C . Assume the specific heat capacity of water under t
Serhud [2]

Answer:

The energy required to heat 1.30 kg of water from 22.4°C to 34.2°C is 64,121.2 J

Explanation:

Calorimetry is the measurement of the amount of heat that a body gives up or absorbs in the course of a physical or chemical process.

The sensible heat of a body is the amount of heat received or transferred by a body when undergoing a temperature variation (Δt) without there being a change in physical state. That is, when a system absorbs (or gives up) a certain amount of heat, it may happen that it experiences a change in its temperature, involving sensible heat. Then, the equation for calculating heat exchanges is:

Q = c * m * ΔT

Where Q is the heat or quantity of energy exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature (ΔT=Tfinal - Tinitial).

In this case:

  • c=4.18 \frac{J}{g*K}
  • m= 1.30 kg= 1,300 g (1 kg=1,000 g)
  • ΔT= 34.2 °C - 22.4 °C= 11.8 °C= 11.8 °K  Being a temperature difference, it is independent if they are degrees Celsius or degrees Kelvin. That is, the temperature difference is the same in degrees Celsius or degrees Kelvin.

Replacing:

Q=4.18 \frac{J}{g*K}*1,300 g*11.8 K

Q= 64,121.2 J

<u><em>The energy required to heat 1.30 kg of water from 22.4°C to 34.2°C is 64,121.2 J</em></u>

4 0
3 years ago
Brainly.com
Inga [223]

The correct answer is  1.6 × 10¹⁰ .

The volume of ice chunk can be calculated by using the formula length × breadth × height

The length of the ice chunk given is 98 m, the breadth of the ice chunk given is 25 m and the thickness of the ice chunk given is 750 m,  

= 98 × 25 × 750 × 0.000189

= 347.9 m³

= 3.831 × 10¹⁴ gal

Water in swimming pool is 24000 gal

Therefore, number of pools that can be filled = 3.831 × 10¹⁴ / 24000

= 1.596 × 10¹⁰  

= 1.6 × 10¹⁰  


3 0
4 years ago
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