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alisha [4.7K]
3 years ago
9

Andre adds a spoonful of baking soda to a glass of vinegar. Bubbles begin to appear in the vinegar. The bubbles signal the forma

tion of a(n) __________.
A.
compound
B.
mixture
C.
element
D.
atom
Chemistry
2 answers:
Bezzdna [24]3 years ago
4 0
 Andre adds a spoonful of baking soda to a glass of vinegar. Bubbles begin to appear in the vinegar. The bubbles signal the formation of a compound. I hope the answer helped you.
marishachu [46]3 years ago
3 0

Its A the answer is a

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The different unit cell types have a different packing efficiency. The simple cubic has the least efficient packing and the face
kozerog [31]

Answer:

The answer is "52.8".

Explanation:

Please find the graph file in the attachment.

They have the atoms in 8 corners with one unit cell in an one so mesh (SCC).

Atoms throughout the corner contribute \frac{1}{8}to both the cell unit

Atom number per SCC unit cell, Z = (8 \times \frac{1}{8}) = 1

Let 'r' become the atom's radius.  r = 3.43\times 10^{-8}\ \ cm

We can see from the diagram that edge length AB = a = 2r

Packing\  efficiency = \frac{(1 \ atom \ Volume  \times Z)}{Volume \ of \ unit\ cell \times  100}\\\\

                                 = \frac{\frac{4}{3}\times \pi \times r^3 \times 1}{a^3 \times 100}\\\\=\frac{\frac{4}{3}\times \pi \times r^3 \times 1}{(2r)^3 \times 100}  \\\\=\frac{\frac{4}{3}\times \pi \times( 3.43\times 10^{-8}cm)^3 \times 1}{(2\times 3.43\times 10^{-8}cm)^3 \times 100}\\\\= 52.8 \%

7 0
3 years ago
A scients produces zinc iodide (Zn).
DiKsa [7]

Answer im a little confused what exactly you need answered. please clarify

Explanation:

7 0
3 years ago
Determinar los números cuánticos del electrón desapareado en el átomo del cloro (Z = 17) y diga si es paramagnético
Musya8 [376]

Answer:

n = 3

l = 1

ml = +1

ms = +1/2

Es paramagnético

Explanation:

Siguiendo las reglas de llenado de orbitales, los 17 electrones del cloro se llenan así:

1S = <u>⇅</u>

2S = <u>⇅</u>

2P = <u>⇅</u> <u>⇅</u> <u>⇅</u>

3S = <u>⇅</u>

3P = <u>⇅</u> <u>⇅</u> <u>↑</u>

<u />

El número cuántico principal n, es el nivel energético donde se encuentra este electrón:

n = 3 (Porque está en el orbital 3P

El número cuántico secundario, l, para el orbital 3P es  = 1:

l = 1

El número cuántico magnético, ml, es determinado por la posición del electrón. Como está en el tercer orbital 3P:

ml = +1

Y el número cuántico de spin, ms (↑ = +1/2; ↓ = -1/2)=

ms = +1/2

Dado que el último electrón se encuentra desapareado, el cloro es paramagnético dado que el espín de el último electrón no tiene su electrón complementario haciendo que este compuesto pueda interactuar con un campo magnético.

3 0
3 years ago
The student's lab manual says to mix some of his Na2CO3 solution with an aqueous solution of copper(II) sulfate (CuSO4)
lord [1]

Explanation:

When the student mixed the solution sodium carbonate with solution of copper(II) sulfate ; Copper Hydroxocarbonate , sodium sulfate and carbon dioxide gas was obtained as a products.

The balanced chemical reaction

2Na_2CO_3+2CuSO_4\rightarrow Cu_2(OH)_2CO_3+2Na_2SO_4+CO_2

Where:

Cu_2(OH)_2CO_3 = Copper(II) Hydroxocarbonate

Na_2CO_3 = Sodium carbonate

CuSO_4 = Copper(II) sulfate

Na_2SO_4 = Sodium sulfate

CO_2 = Carbon-dioxide

3 0
4 years ago
The higher the pH, the less acidic the solution
marshall27 [118]

Answer:

<em>yh thats true lol, ty for that very interesting fact</em>

6 0
3 years ago
Read 2 more answers
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