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valina [46]
3 years ago
12

The value of\[\left( 1-{1\over3} \right)\left( 1-{1\over4} \right)\left( 1-{1\over5} \right)....\left( 1-{1\over n} \right)\]is

equal to??
Mathematics
1 answer:
Oliga [24]3 years ago
6 0
Example 1<span>

<span><span>verbose explicit high3 <span>plus </span>4 <span>cross </span>2 <span>minus </span><span>minus </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>1 3</span><span>verbose explicit high semantics3 <span>plus </span>4 <span>times </span>2 <span>minus </span><span>negative </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>13</span><span>verbose explicit high semantics high3 <span>plus </span>4 <span>times </span>2 <span>minus </span><span>negative </span>2 <span>equals </span>3 <span>plus </span>8 <span>plus </span>2 <span>equals </span>13</span></span>
</span>

For most fractions, the beginning is indicated with "start fraction", the horizontal line is indicated with "over", and the end of the fraction is indicated by "end fraction". For the semantic interpretation, most numeric fractions are spoken as they are in natural speech. Also if a number is followed by a numeric fraction, the word "and" is spoken in between.

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If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{
Elis [28]

Answer:

x = 36

Step-by-step explanation:

x - 12\sqrt{x} + 36 = 0

Subtract x and 36 from both sides.

-12\sqrt{x} = -x - 36

Divide both sides by -1.

12\sqrt{x} = x + 36

Square both sides.

144x = x^2 + 72x + 1296

Subtract 144x from both sides.

0 = x^2 - 72x + 1296

Factor the right side.

0 = (x - 36)^2

x - 36 = 0

x = 36

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

x - 12\sqrt{x} + 36 = 0

36 - 12\sqrt{36} + 36 = 0

36 - 12\times 6 + 36 = 0

36 - 72 + 36 = 0

0 = 0

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

6 0
3 years ago
Two angles are supplementary if the sum of their measures is 180 degrees. find two supplementary angles such that the smaller is
kaheart [24]
If the larger angle is x and the smaller angle is y, y=(1/2)x+30 since it's 30 more than 1/2 of it. In addition, x+y=180 since they are supplementary. Plugging y=(1/2)x+30 into that, we get x+x/2+30=180=1.5x+30. Subtracting 30 from both sides, we get 1.5x=150. Next, we can divide both sides by 1.5 to get x=100 and y=(1/2)*100+30=50+30=80
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Answer:

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Step-by-step explanation:

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3 years ago
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