A crate of mass 10.0 kg is pulled up a roughincline with an initial speed of 1.50m/s. The pulling forceis 100N parallel to the i
ncline, which makes an angle of 20.0 withthe horizontal. The coefficient of kinetic friction is 0.400,and the crate is pulled 5.00m.
A) How much work is done by the gravitational force on thecrate?
B) Determine the increase in internal energy of the crate-inclinesystem owing to friction.
C) How much work is done by the 100N force on the crate?
D)What is the change in kinetic energy of the crate?
E) What is the speed of the crate after being pulled 5.00m?
A) How much work is done by the gravitational force on thecrate?
B) Determine the increase in internal energy of the crate-inclinesystem owing to friction.
C) How much work is done by the 100N force on the crate?
D)What is the change in kinetic energy of the crate?
E) What is the speed of the crate after being pulled 5.00m?
1 answer:
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Answer:
The maximum speed of the wing tip is 1.25 m/s
Explanation:
In simple harmonic motion, the body experiences a restoring force whose magnitude is directly proportional to the distance from its mean position and its direction is towards the mean position.
The speed in the case of simple harmonic motion is given by the equation :
v = Aωsinωt
Here A is maximum displacement, t is time and ω is the angular frequency of oscillation.
For maximum speed, sinωt = 1 . So, the above equation becomes:
v = Aω
But, ω = 2πf , here f is the frequency of oscillation. So,
v = A x 2πf .....(1)
In this problem,
Frequency of oscillation, f = 40 Hz
Total distance between the upper and lower limits of motion of wing tip is equal to the twice of maximum displacement of the wing tip from the equilibrium position, i.e. ,
2 x A = 1 cm
A = 0.5 cm = 0.5 x 10⁻² m
Substitute the value of f and A in equation (1).
v = 1.25 m/s