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Schach [20]
3 years ago
9

help asap please. Which of the following is one part of a chemical formula? a. A number that shows the total atomic mass of the

substance b. The full name of each element shown c. The symbol of each element in the substance d. A number that shows the total number of chemical bonds
Physics
2 answers:
rosijanka [135]3 years ago
7 0

Answer: C

Explanation:

Chemical formula of any element, chemical or compound contains the symbol of the elements involved, the number of molecules and the number of atoms present as a subscript.

For instance, Nacl is a chemical formula for sodium chloride. The chemical combination of sodium and chlorine. While Hcl is a chemical formula for hydrochloric acid - the chemical combination of hydrogen and chlorine.

According to the question given above,

The symbol of each element in the substance is one of the part of the chemical formula.

Daniel [21]3 years ago
3 0

Answer:

C. The symbol each element shown

Explanation:

ln order to find the chamival fotmula you need the element

P.S. I got it right

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Explanation:

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3 years ago
A T-shirt cannon can shoot a 0.085 kg T-shirt at nearly 30 m/s. The T-shirt cannon has a mass of 33 kg. If the initial net momen
IgorLugansk [536]

Answer:

Approximately 0.077\; {\rm m\cdot s^{-1}} (assuming that external forces on the cannon are negligible.)

Explanation:

If an object of mass m is moving at a velocity of v, the momentum p of that object would be p = m\, v.

Momentum of the t-shirt:

\begin{aligned} p(\text{t-shirt}) &= m(\text{t-shirt}) \, v(\text{t-shirt}) \\ &= 0.085\; {\rm kg} \times 30\; {\rm m \cdot s^{-1}} \\ &= 2.55 \; {\rm kg \cdot m \cdot s^{-1}} \end{aligned}.

If there is no external force (gravity, friction, etc.) on this cannon, the total momentum of this system should be conserved. In other words, if p(\text{cannon}) denote the momentum of this cannon:

p(\text{t-shirt}) + p(\text{cannon}) = 0.

p(\text{cannon}) = -p(\text{t-shirt}) = -2.55\; {\rm kg \cdot m \cdot s^{-1}}.

Rewrite p = m\, v to obtain v = (p / m). Since the mass of this cannon is m(\text{cannon}) = 33\; {\rm kg}, the velocity of this cannon would be:

\begin{aligned} v(\text{cannon}) &= \frac{p(\text{cannon})}{m(\text{cannon})} \\ &= \frac{-2.55\; {\rm kg \cdot m \cdot s^{-1}}}{33\; {\rm kg}} \\ &\approx 0.077\; {\rm m \cdot s^{-1}}\end{aligned}.

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Answer:

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