Answer:
Vs/c = 20 [m/s]
Explanation:
This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.
We are asked for the velocity of the sailboat with respect to an observer located in the canoe.
![V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s]](https://tex.z-dn.net/?f=V_%7Bs%2Fc%7D%3DV_%7Bsailboat%7D-V_%7Bcanoe%7D%5C%5CV_%7Bs%2Fc%7D%3D15-%28-5%29%5C%5CV_%7Bs%2Fc%7D%3D20%5Bm%2Fs%5D)
Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.
Answer:
Explanation:
A. The kinetic energy is the same as the initial potential energy:
PE = mgh = (215 N)(2.0 M) = 430 J
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B. The velocity achieved by falling from a height h is given by ...
v = √(2gh)
v = √(2·9.8 m/s^2·2 m) = √(39.2 m^2/s^2)
v ≈ 6.26 m/s
Explanation:
Given that,
The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.
The mass of each orange is 198 g
We know that,
1 kg = 1000 g
10.222 kg = 10.222×1000 g
Let there are n number of oranges. So,
It means she can send 52 oranges and it is maximum quantity.
Answer c, velocity would be the answer.
Answer:
k = 17043.5 N/m = 17.04 KN/m
Explanation:
First we need to find the force applied by safe pn the spring:
F = Weight of Safe
F = mg
where,
F = Force Applied by the safe on the spring = ?
m = mass of safe = 800 kg
g = 9.8 m/s²
Therefore,
F = (800 kg)(9.8 m/s²)
F = 7840 N
Now, using Hooke's Law:
F = kΔx
where,
K = Spring Constant = ?
Δx = compression = 46 cm = 0.46 m
Therefore,
7840 N = k (0.46 m)
k = 7840 N/0.46 m
<u>k = 17043.5 N/m = 17.04 KN/m</u>
