Answer:
The answer is a, the dirty cloths, water and detergent.
Explanation:
The answer is the above selected because the inputs basically represent the data that are passed through the system to generate the output.
In this case, the inputs are the aforementioned in the answer while the possible output would literally be the clean cloths.
Answer:
Atomic radius decreases moving from left to right across a period.
Explanation:
When we move left to right across a period, the size of atoms generally decreases. It is because within the period the outer electrons are in same valence shell and the number of electrons and proton increases moving from left to right across the the period. It increases the effective nuclear charge resulting in the increased attraction of electron to the nucleus that causes the decreased radius of the atoms.
Answer:
Option 3
Explanation:
O Option C is NEGATIVELY CHARGED, meaning it has GAINED ELECTRONS resulting in a GREATER number of ELECTRONS than PROTONS.
Answer:
Explanation:
The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also<u> assuming level road</u>.
E = ½mv² = ½(1000)30² = 450,000 J
Answer:
Part a)
![I = 1.5 kg m^2](https://tex.z-dn.net/?f=I%20%3D%201.5%20kg%20m%5E2)
Part b)
![I = 0.75 kg m^2](https://tex.z-dn.net/?f=I%20%3D%200.75%20kg%20m%5E2)
Part c)
![I = 1.5 kg m^2](https://tex.z-dn.net/?f=I%20%3D%201.5%20kg%20m%5E2)
Explanation:
Part a)
Moment of inertia of the system about an axis passing through B and C is given as
![I = mL^2 + mL^2 + m(0) + m(0)](https://tex.z-dn.net/?f=I%20%3D%20mL%5E2%20%2B%20mL%5E2%20%2B%20m%280%29%20%2B%20m%280%29)
![I = 2mL^2](https://tex.z-dn.net/?f=I%20%3D%202mL%5E2)
![I = 2(3 kg)(0.50^2)](https://tex.z-dn.net/?f=I%20%3D%202%283%20kg%29%280.50%5E2%29)
![I = 1.5 kg m^2](https://tex.z-dn.net/?f=I%20%3D%201.5%20kg%20m%5E2)
Part b)
Moment of inertia of the system about an axis passing through A and C is given as
![I = m(0^2) + m(\frac{L}{\sqrt2})^2 + m(0) + m(\frac{L}{\sqrt2})^2](https://tex.z-dn.net/?f=I%20%3D%20m%280%5E2%29%20%2B%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2%20%2B%20m%280%29%20%2B%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2)
![I = 2m\frac{L^2}{2}](https://tex.z-dn.net/?f=I%20%3D%202m%5Cfrac%7BL%5E2%7D%7B2%7D)
![I = (3 kg)(0.50^2)](https://tex.z-dn.net/?f=I%20%3D%20%283%20kg%29%280.50%5E2%29)
![I = 0.75 kg m^2](https://tex.z-dn.net/?f=I%20%3D%200.75%20kg%20m%5E2)
Part c)
Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square
![I = m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2](https://tex.z-dn.net/?f=I%20%3D%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2%20%2B%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2%20%2B%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2%20%2B%20m%28%5Cfrac%7BL%7D%7B%5Csqrt2%7D%29%5E2)
![I = 4m\frac{L^2}{2}](https://tex.z-dn.net/?f=I%20%3D%204m%5Cfrac%7BL%5E2%7D%7B2%7D)
![I = 2(3 kg)(0.50^2)](https://tex.z-dn.net/?f=I%20%3D%202%283%20kg%29%280.50%5E2%29)
![I = 1.5 kg m^2](https://tex.z-dn.net/?f=I%20%3D%201.5%20kg%20m%5E2)