Answer: A.Validate and implement the results.
The final step in a forecasting system is to validate and implement the results. This can be similar to a presentation. After going through all the steps from the planning, researching, and gathering of data, making the forecast, validating and implementing the results will be the last thing that needs to be done.
In a particle accelerator a positron (C= +1.6 x 10-19) travels through a perpendicular magnet field with a magnitude
of 3.1 x 10-2 T. At what speed must the positron travel in order for it to experience a force of 4.75 x 10-14 N?
28. An alpha particle (2 protons and 2 neutrons) experiences a downward force of 2.9 x 10-14 N while traveling in a
magnetic field with a strength of 5.1 x 10-19 T pointing to the north. Find the speed of the particle and the direction
it must be traveling in.
29. Find the length of a wire if it experiences a .63N force when it travels through a magnetic field with a strength of
0.85T whilst carrying 5.0 amps of current.
30. A coil with 462 turns of wire, a total resistance of 36Ω , and a cross-sectional area of 0.25 m2
is positioned with its
plane perpendicular to the field of a powerful electromagnet. What average current is induced in the coil during the 0.37s
that the magnetic field drops from 3.1 T to 0.0 T?
31. A step-up transformer has a potential difference across the primary of 28 V and a potential difference across the
secondary of 3.0 × 104
V. There are 28 turns in the primary coil. How many turns are in the secondary?
32. A step-up transformer is used to create a potential difference of 1.6872 × 105
V across the secondary. The potentia
Answer:
66.375 x 10⁻⁶ C/m
Explanation:
Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as
;
∅ = Q / ε₀ -----------------(i)
Where;
∅ = 7.5 x 10⁵ Nm²/C
ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²
Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;
7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)
Solve for Q;
Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²
Q = 66.375 x 10⁻⁷ C
Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e
L = Q / l ----------------------(ii)
Where;
Q = 66.375 x 10⁻⁷ C
l = length of the rod = 10.0cm = 0.1m
Substitute these values into equation (ii) as follows;
L = 66.375 x 10⁻⁷C / 0.1m
L = 66.375 x 10⁻⁶ C/m
Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.
You will need to turn this into scientific notation, so:
1.176 × 10^1 cm^2
To two significant figures means to two digits so since 7 is greater than 5, you will need to round up.
Final answer is:
1.2×10^1 cm^2
Answer:
Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all - option A
Explanation:
Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all; the reason being that: no magnetic field is being produced by a charge that is static. Only a moving charge can produce a magnetic effect. And the magnet can not have any torque due to its own magnetic lines of force.
