What amount of heat is absorbed by 257 g of water heated from 18° C to 63° C? The specific heat of water is 4.18 J/g°C.
1 answer:
Answer:
Q = 48341.7 Joules.
Explanation:
<u>Given the following data;</u>
Mass, m = 257g
Initial temperature, T1 = 18°C
Final temperature, T2 = 63°C
Specific heat capacity of water, c = 4.18 J/g°C.
*To find the quantity of heat absorbed*
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 63 - 18
dt = 45°C
<em>Substituting the values into the equation, we have;</em>
<em>Q = 48341.7 Joules.</em>
<em>Therefore, the amount of heat absorbed is 48341.7 Joules</em>.
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If the frequency of the source is increased the current in the circuit will decrease.
Explanation:
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Where;
V is the voltage in the AC circuit
Z is the impedance
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R is the resistance
is the inductive reactance
= ωL = 2πfL
where;
L is the inductance
f is the frequency of the source
Finally, the current in the circuit is given as;
From the equation above, an increase in frequency (f) will cause a decrease in current (I).
Therefore, If the frequency of the source is increased the current in the circuit will decrease.