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Alla [95]
3 years ago
12

What amount of heat is absorbed by 257 g of water heated from 18° C to 63° C? The specific heat of water is 4.18 J/g°C.

Physics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

Q = 48341.7 Joules.

Explanation:

<u>Given the following data;</u>

Mass, m = 257g

Initial temperature, T1 = 18°C

Final temperature, T2 = 63°C

Specific heat capacity of water, c = 4.18 J/g°C.

*To find the quantity of heat absorbed*

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2 - T1

dt = 63 - 18

dt = 45°C

<em>Substituting the values into the equation, we have;</em>

Q = 257*4.18*45

<em>Q = 48341.7 Joules.</em>

<em>Therefore, the amount of heat absorbed is 48341.7 Joules</em>.

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