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Paladinen [302]
3 years ago
15

Suppose you are spinning a child around in a circle by her

Physics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

25 N

Explanation:

Sum of the forces on the child in the radial direction:

∑F = ma

T = m v² / r

T = (25 kg) (1 m/s)² / (1 m)

T = 25 N

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With good tires and breaks, a car traveling 50 mi/hr on dry pavement can travel 400 ft when the driver reacts to something he se
Bogdan [553]

Answer:6.72 m/s^2

Explanation:

Given

initial velocity u=50 mi/hr\approx 73.33 ft/s

Distance traveled before stopping s=400 ft

using equation of

v^2-u^2=2as

where v=final velocity

u=initial Velocity

a=acceleration

s=displacement

v=0 as car stops after travelling 400 ft

0-73.33^2=2\times a\times 400

a=-6.72 m/s^2

negative sign indicates it is deceleration

3 0
3 years ago
A toy rocket fires its engines to launch it straight up from rest. After a
sweet [91]

i will say that 32.2m s2 bt am not sure

7 0
3 years ago
Hypothesis what is it
Naya [18.7K]

Explanation:

hope it helps.

<h3>stay safe healthy and happy.</h3>

7 0
3 years ago
A nonprofit organization posted an article in the local newspaper about a recent marathon. The marathon raised money for vaccina
mr Goodwill [35]

Answer:

An original funding source.

Explanation:

Non profit organization planned a marathon through which the money was raised for the vaccinations help, hence; here they are showing the original funding source, that is the number of runners and the amount raised by them.

3 0
4 years ago
Read 2 more answers
What is the density (in kg/m3) of a woman who floats in freshwater with 4.92% of her volume above the surface
kipiarov [429]

Answer:

The density of the woman is 950.8 kg/m³

Explanation:

Given;

fraction of the woman's volume above the surface = 4.92%

then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%

the specific gravity of the woman = \frac{95.08}{100 } = 0.9508

The density of the woman is calculate as;

Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman  = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water

Density of fresh water = 1000 kg/m³

Density of the woman = 0.9508 x 1000 kg/m³

Density of the woman = 950.8 kg/m³

Therefore, the density of the woman is 950.8 kg/m³

4 0
3 years ago
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