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tigry1 [53]
3 years ago
14

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 29.4 m/s2 . Th

e acceleration period lasts for time 5.00 s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s2 .
Physics
1 answer:
gtnhenbr [62]3 years ago
8 0

Hi there!

We can begin by using the following formulas:

Δd = vit + 1/2at²

vf² = vi² + 2ad

v = at

We can break this problem into 2 parts:

Distance traveled with acceleration:

Δd = vi(t) + 1/2at²

The rocket starts from rest so disregard the "vi(t)":

Δd = 1/2at²

Plug in the given acceleration and time:

Δd = 1/2(29.4)(5)²

Δd = 367.5 m

Distance traveled after thrust stops:

Find the displacement up to the top of the trajectory using the equation:

vf² = vi² + 2ad, where vf = 0 m/s

Calculate the initial velocity using the equation v = at:

v = (29.4)(5) = 147 m/s

Use the above equation and plug in the given values:

0² = (147)² + 2(-9.8)d

Solve for d:

0 = 21,609 - 19.6d

19.6d = 21,609

d = 1,102.5 m

Add the two displacements:

d1 + d2 = 1,470 m

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The electron dot diagram shows the arrangement of dots without identifying the element.
olasank [31]

<em>Answer: </em>tellurium (Te)

<em>atomic number = 52 ,</em>

<em>Number of energy levels = 5;</em>

              First energy level = 2

         Second energy level = 8

             Third energy level = 18

           Fourth energy level = 18

               Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>


5 0
3 years ago
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Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum?
Flauer [41]
Hey there!

So we know that m*v=P.
And in this question m=30
v=5 m/s
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps! :)
5 0
3 years ago
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Compute the expected shell-model quadrupole moment of 209Bi () and compare with the experimental value, - 0.37 b
Over [174]

Answer:

0.22 b

Explanation:

Quadrupole moment of the nucleon is,

Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}

And also,

R^{2}=R^{2} _{0}A^{\frac{2}{3} }

And, R _{0}=1.2\times 10^{-15}m

Now,

Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }

For Bismuth j=\frac{9}{2} and A is 209.

Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b

3 0
3 years ago
A 90 kg astronaut Travis is stranded in space at a point 12 m from his spaceship. In order to get back to his ship, Travis throw
insens350 [35]

Answer:

Explanation:

This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:

[m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a which, in words, is

The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:

[(90.0)(0)+(.50)(0)]_b=[(90.0)(v)+(.50)(-4.0)]_a

Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).

0 = 90.0v - 2.0 and

2.0 = 90.0v so

v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.

12 = .022t and

t = 550 seconds, which is the same thing as 9.2 minutes

7 0
3 years ago
Definition: A potential path for the flow of electricity with at least one gap in the path that prevents this flow. The gap is u
Andreas93 [3]

Answer:

Open circuit

Explanation:

An open circuit is simply an electrical circuit that is not complete. In such a circuit, there is a gap and this will not allow the electric current to pass through.

Despite all the elements being complete in the circuit, an open circuit will halt the flow of electric current and will not do deliver the necessary energy it is supposed to.

In such a circuit, the wires are cut of and not connected properly.

The reverse is a closed circuit.

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3 years ago
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