1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Papessa [141]
2 years ago
5

Which layer of the sun gives off the visible light normally seen from earth?

Physics
1 answer:
Amiraneli [1.4K]2 years ago
3 0
Most of the energy we receive from Sun is the visible light or whit light emitted from the photosphere. The photosphere is one of the most coolest region of the Sun. The photosphere is the visible surface of the Sun that we are most familiar with.
You might be interested in
Jonas and his family are moving to another part of the city. As Jonas, his brother, and his Dad were driving one of the trucks f
vredina [299]

Answer:

i think the answer would be:Jonas’ brother gets out of the cab of the truck and sits in the back of the truck with the furniture. With less mass, they should be able to push the truck to the gas station.

Explanation:

5 0
3 years ago
Read 2 more answers
Before digital filmmaking, what tool was used to control the speed of movement on the screen after filming?
nikitadnepr [17]

Answer:

The appropriate response is "Optical printer ".

Explanation:

  • A photographic printer used mostly for optical aberrations, comprised simply of either a camera that captures the frame to expand, minimize, deform, respectively. through magnifying lenses.
  • A projector that always, as distinct from some kind of touch printer, transferred the image to something like the printing supply.
4 0
3 years ago
A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back
castortr0y [4]

Answer:

a) 5 m/s downwards

b) 17.86 m/s

c) 24.82 m/s

d) 0.228

Explanation:

We can set the frame of reference with the origin on the top of the building and the X axis pointing down.

The rock will be subject to the acceleration of gravity. We can use the equation for position under constant acceleration and speed under constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a * t^2

V(t) = V0 + a * t

In this case

X0 = 0

V0 = -5 m/s

a = 9.81 m/s^2

To know the speed it will have when it falls back past the original point we need to know when it will do it. When it does X will be 0.

0 = -5 * t + 1/2 * 9.81 * t^2

0 = t * (-5 + 4.9 * t)

One of the solutions is t = 0, but this is when the rock was thrown.

0 = -5 + 4.69 * t

4.9 * t = 5

t = 5 / 4.9

t = 1.02 s

Replacing this in the speed equation:

V(1.02) = -5 + 9.81 * 1.02 = 5 m/s (this is speed downwards because the X axis points down)

When the rock is at 15 m above the street it is 15 m under the top of the building.

15 = -5 * t + 1/2 * 9.81 * t^2

4.9 * t^s -5 * t - 15 = 0

Solving electronically:

t = 2.33 s

At that time the speed will be:

V(2.33) = -5 + 9.81 * 2.33 = 17.86 m/s

When the rock is about to reach the ground it is at 30 m under the top of the building:

30 = -5 * t + 1/2 * 9.81 * t^2

4.9 * t^s -5 * t - 30 = 0

Solving electronically:

t = 3.04 s

At this time it has a speed of:

V(3.04) = -5 + 9.81 * 3.04 = 24.82 m/s

---------------------

Power is work done per unit of time.

The work in this case is:

L = Ff * d

With Ff being the friction force, this is related to weight

Ff = μ * m * g

μ: is the coefficient of friction

L = μ * m * g * d

P = L/Δt

P = (μ * m * g * d)/Δt

Rearranging:

μ = (P * Δt) / (m * g * d)

1 horsepower is 746 W

20 minutes is 1200 s

μ = (746 * 1200) / (100 * 9.81 * 4000) = 0.228

8 0
2 years ago
Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests o
Andrew [12]

Answer:

The magnitude of the angular acceleration ∝ = \frac{rxF}{2.8[tex]r^{2}}[/tex]

Explanation:

The angular acceleration ∝ is equal to the torque (radius multiplied by force) divided by the mass times the square of the radius. The magnitude of angular acceleration ∝ will have the equation above but we have to replace the mass in the equation by 2.8kg as stated.

7 0
2 years ago
Why do all objects above earth's surface have gravitational potential energy
gayaneshka [121]
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. The most common use of </span>gravitational potential energy<span> is for an object near the surface of the Earth where the </span>gravitational<span> acceleration can be assumed to be constant at about 9.8 m/s</span>2<span>.</span>
6 0
3 years ago
Other questions:
  • How far will a cheetah travel if it runs at 30 m/s for 60s?
    14·1 answer
  • Blocks 1 and 2 of masses m1 and m2, respectively are connected by a light string, as show above. These blocks are further connec
    7·2 answers
  • One way to decrease the inertia of an object is to
    8·2 answers
  • Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star.
    11·1 answer
  • An object of mass 11kg is falling in air and experiences a force due to air resistance of 35N. Determine the magnitude of net fo
    14·1 answer
  • Match each item to its best description.
    6·2 answers
  • Which of the following are likely to form a covalent bond?
    15·2 answers
  • A flat coil of wire has an area A, N turns, and a resistance R. It is situated in a magnetic field, such that the normal to the
    7·1 answer
  • A car travels 90 meters north in 15 seconds. Then turns around and travels at 40 meters south in 5.0 seconds. what is the averag
    6·1 answer
  • QUICK HELP ILL MARK U BRAINLIEST
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!