Hello!
1) What is the limiting reactant?The chemical equation for this reaction is:
2Al(OH)₃ → Al₂O₃ + 3H₂OThe
Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a
decomposition reaction. So,
the limiting reactant is Al(OH)₃.2) How many grams of water are produced?The chemical equation for this reaction is:
2Al(OH)₃ → Al₂O₃ + 3H₂O
So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:

So,
6,17 grams of Water are produced.
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Answer:
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The molarity of KOH is 0.1055 M
<u><em> calculation</em></u>
Step 1: write the equation for reaction between H₂C₂O₄.2H₂O and KOH
H₂C₂O₄.2H₂O + 2 KOH → K₂C₂O₄ +4 H₂O
step 2: find the moles of H₂C₂O₄.2H₂O
moles = mass÷ molar mass
from periodic table the molar mass H₂C₂O₄.2H₂O= (1 x2) +(12 x2) +(16 x4) + 2(18)=126 g/mol
= 0.2000 g ÷ 126 g/mol =0.00159 moles
step 3: use the mole ratio to calculate the moles of KOH
H₂C₂O₄.2H₂O : KOH is 1:2
therefore the moles of KOH =0.00159 x 2 = 0.00318 moles
step 4: find molarity of KOH
molarity = moles/volume in liters
volume in liters = 30.12/1000=0.03012 L
molarity is therefore = 0.00318/0.03012 =0.1055 M