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3 years ago

What is the name of the covalent compound CCl4?

1 answer:

4 0

Think, first, about the type of molecule or formula unit you have (covalent or ionic). In this case, it is a covalent molecule. You start with the carbon. You could say monocarbon, but if it is just said to be carbon it is assumed to be one. Then you take the prefix for 4 and tack it on to the beginning of the chlorine. For this, the name is carbon tetrachloride.

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Answer the questions in the table below about the shape of the phosphorus hexachloride (PCI^1_6) anion. What word or two-word ph

REY [17]

Shape of PCl₆⁻¹, is octahedral.

Hybrdisation of PCl₆⁻¹ is sp³d².

This can be seen the image attached.

The angle between phosphorous and chlorine is 90⁰C. As it has octahedral geometry.

So the answer is as follows:

Shape of PCl₆⁻¹, is octahedral.

Hybrdisation of PCl₆⁻¹ is sp³d².

The angle between phosphorous and chlorine is 90⁰C.

6 0

3 years ago

Air masses carry their own weather.<br> True<br> False<br> The question is number 8

frozen [14]

True because I had the test

8 0

2 years ago

For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of

Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O; Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

7 0

3 years ago

Read 2 more answers

Im hvaing a hard time getting the right answer

Tanya [424]

Answer:

$V=23.9mL$

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

$n=2.49g*\frac{1mol}{125.55 g}=0.0198mol$

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

$M=\frac{n}{V}\\\\V=\frac{n}{M}$

By plugging in the moles and molarity, we obtain:

$V=\frac{0.0198mol}{0.830mol/L}=0.0239L$

Which in mL is:

$V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL$

Best regards!

6 0

3 years ago

Determine if the results of the following word problem adhere to the Law of Conservation of Mass. 1. A chemist combines 4.9 g of

KiRa [710]

Answer: The results agree with the law of conservation of mass

Explanation:

The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. On the reactant side, the total mass of reactants is 14.3g and the total product masses is also 14.3g. That implies that no mass was !most in the reaction. The sum of masses on the left hand side corresponds with sum of masses on the right hand side of the reaction equation.

4 0

3 years ago