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Vaselesa [24]
3 years ago
11

A balanced equation tells you the mole ratio of all reactants and products. Using the chemical reaction below how many moles of

NH3 are made when 3 moles of hydrogen gas are used?
2N2 + 3H2 ---> 2NH3
Chemistry
2 answers:
Hunter-Best [27]3 years ago
6 0
From  the  reaction  above    2  moles  of  N2  reacted  with  3  moles  of  H2  to  give  2  moles of   ammonia
THese  implies  that   the   mole  ratio  of  hydrogen  to  ammonia   is   3:2
Therefore  if   3  moles  of  hydrogen   were  used  the  moles  of  ammonia  is  therefore
(3 x2)/3=  2moles
vichka [17]3 years ago
5 0
<span>By using the mole ratio, we can determine that 2 moles of NH3 are made when 3 moles of hydrogen gas are present. The numbers in front of the chemicals tell us the relative amounts consumed and produced. Since there is a 3 in front of H2 and a 2 in front of NH3, this tells us that for every 3 moles of H2 gas used, 2 moles of NH3 are made.</span>
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8 0
3 years ago
Use Hess's Law to calculate the enthalpy change for the reaction
Marysya12 [62]

Answer:

ΔH = 125.94kJ

Explanation:

It is possible to make algebraic sum of reactions to obtain ΔH of reactions (Hess's law). In the problem:

1. 2W(s) + 3O2(g) → 2WO3(s) ΔH = -1685.4 kJ

2. 2H2(g) + O2(g) → 2H2O(g) ΔH = -477.84 kJ

-1/2 (1):

WO3(s) → W(s) + 3/2O2(g) ΔH = 842.7kJ

3/2 (2):

3H2(g) + 3/2O2(g) → 3H2O(g) ΔH = -716.76kJ

The sum of  last both reactions:

WO3(s) + 3H2(g) → W(s) + 3H2O(g)

ΔH = 842.7kJ -716.76kJ

<h3>ΔH = 125.94kJ </h3>
3 0
3 years ago
Answer question number 2
kipiarov [429]

Answer:

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3 0
3 years ago
What happens if you are in a swimming<br> pool and you push a beach ball down<br> with your hands?
Aleksandr-060686 [28]

Answer:

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7 0
3 years ago
Beryllium oxide, Beo, is an electrical insulator. How
egoroff_w [7]

Answer:

There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

Explanation:

We can calculate the number of moles (η) of BeO as follows:

\eta = \frac{m}{M}

Where:

m: is the mass = 250 g

M: is the molar mass = 25.0116 g/mol

Hence, the number of moles is:

\eta = \frac{250 g}{25.0116 g/mol} = 10.0 moles

Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.  

I hope it helps you!

3 0
3 years ago
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