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denpristay [2]
3 years ago
9

What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7

52 torr and the level of mercury in the arm connected to the container is 9.60 cm higher than the level of mercury open to the atmosphere?
Chemistry
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

The pressure in the gas is 656mmHg

Explanation:

In calculating the pressure of the gas;

step 1: convert the height of the mercury arm to mmHg

9.60cm = 96.0 mmHg

step 2: convert 752 torr to mmHg

I torr is 1 mmHg

752 torr = 752mmHg

Step 3: since the level of mercury in the container is higher than the level of mercury exposed to the atmosphere, we substrate the values to obtain our pressure.

So, 752mmHg - 96mmHg = 656mmHg

The pressure in the gas container is therefore 656mmHg.

N. B : if the mercury arm is in lower position, you add.

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m(water) = 32 g + 16 g - 33,6 g.
3) </span><span>0.60 g calcium carbonate + 0.48 g sodium hydroxide --> 0,63 g sodium carbonate + 0.45 g calcium.
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6 0
3 years ago
What is Q= mc delta t
Mariulka [41]

Answer:

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,

The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.

Consider that both oil and water have same mass of 5g and change in temperature is 15 K. Thus amount of heat thy absorbed to raise the temperature is,

For oil:

Q = m.c. ΔT

Q = 5 g× 1.67 j/g K × 15 K

Q = 125.25 j

For water:

Q = m.c. ΔT

Q = 5 g× 4.18 j/g K × 15 K

Q = 313.5 j

we can observe that water require more heat which is 313.5 j to increase its temperature.

6 0
3 years ago
You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially
nika2105 [10]

Answer :

(a) The heat released by the metal is -312.48 J

(b) The specific heat of the metal is 0.0944J/g^oC

Explanation :

<u>For part A :</u>

Heat released by the metal = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the metal

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

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c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 50.0 g

\Delta T = change in temperature = (T_{final}-T_{initial})=23.2-22.0=1.2^oC

Now put all the given values in the above formula, we get:

q=[(51.5J/^oC\times 1.2^oC)+(50.0g\times 4.184J/g^oC\times 1.2^oC)]

q=312.48J

Thus, the heat released by the metal is -312.48 J

<u>For part B :</u>

q=m\times c\times \Delta T

q = heat released by the metal = -312.48 J

m = mass of metal = 43.1 g

c = specific heat of metal = ?

\Delta T = change in temperature = (T_{final}-T_{initial})=23.2-100=76.8^oC

Now put all the given values in the above formula, we get:

-312.48J=43.1g\times c\times 76.8^oC

c=0.0944J/g^oC

Thus, the specific heat of the metal is 0.0944J/g^oC

8 0
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Sveta_85 [38]

Answer:

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Explanation:

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Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

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Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

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Solving for X,

X = 1 mol × 0.570 mol / 6 mol

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Step 3: Calculate mass of P₄ as,

Mass = Moles × M.Mass

Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

8 0
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