Answer: 8
Explanation:
Non metals which have 4 electrons in the outer shell i.e in the valence shell bond with the other similar non metals having 4 electrons in their valence shell. This bond is known as covalent bond in which the two atoms share their valence electrons with each other in order to complete their valence shell. These atoms seeks to have 8 electrons in order to attain noble gas configuration.
Answer:
remote control, neon and fluorescent lights, wireless transmission, computers, smartphones
Explanation:
Answer:
53.64 m/s
Explanation:
Applying,
a = (v-u)/t............. Equation 1
Where a = acceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
make u the subject of the equation
u = v-at............. Equation 2
From the question,
Given: a = -12 mph/s = -5.364 m/s², t = 10 seconds, v = 0 m/s (comes to stop)
Substitute these values into equation 2
u = 0-(-5.364×10)
u = 0+53.64
u = 53.64 m/s
Answer:
t = 1.15 + .713 = 1.863 [s]
Explanation:
To solve this problem we must use the following kinematic equation, but first we identify the initial data.
vo = 7 [m/s]
yo = 4 [m]
g = 9.81[m/s^2]
![v_{f}=v_{o}-g*t\\0 = 7 - (9.81*t)\\7 = 9.81*t\\t = 0.713[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bo%7D-g%2At%5C%5C0%20%3D%207%20-%20%289.81%2At%29%5C%5C7%20%3D%209.81%2At%5C%5Ct%20%3D%200.713%5Bs%5D)
The final velocity happens at the moment when the maximum height is reached, at this point the final speed is zero.
![y=y_{o}+v_{o}*t-0.5*g*t^{2}\\ y = 0+ (7*0.713)-0.5*9.81*(0.713)^{2}\\ y = 2.5[m]](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Bo%7D%2At-0.5%2Ag%2At%5E%7B2%7D%5C%5C%20y%20%3D%200%2B%20%287%2A0.713%29-0.5%2A9.81%2A%280.713%29%5E%7B2%7D%5C%5C%20y%20%3D%202.5%5Bm%5D)
The total elevation will be 2.5 + 4 = 6.5 [m]
Now using again the total height we can find the final velocity.
![v_{f}^2=v_{o}^2+2*g*y\\v_{f}=\sqrt{2*g*y}\\ v_{f}=\sqrt{2*9.81*6.5}\\ v_{f}=11.3[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E2%3Dv_%7Bo%7D%5E2%2B2%2Ag%2Ay%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%2Ag%2Ay%7D%5C%5C%20v_%7Bf%7D%3D%5Csqrt%7B2%2A9.81%2A6.5%7D%5C%5C%20v_%7Bf%7D%3D11.3%5Bm%2Fs%5D)
With this final velocity we cand find the time.
![v_{f}=v_{i}+g*t\\11.3=0+9.81*t\\11.3=9.81*t\\t=1.15[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bi%7D%2Bg%2At%5C%5C11.3%3D0%2B9.81%2At%5C%5C11.3%3D9.81%2At%5C%5Ct%3D1.15%5Bs%5D)
Now we have to sum the two times, the time it takes to go up and the time it takes to go down.
t = 1.15 + .713 = 1.863 [s]
