Darlene jumps into a swimming pool. She is creating _____. deep water waves impact waves surface currents tidal waves
2 answers:
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A) -2.0 m
Look at the ray diagram attached in the picture, where:
p identifies the location of the object
q identifies the location of the image
F identifies the focus of the mirror
Each tick represents 1 m
We have
p = 6.0 m is the distance of the object from the mirror
f = -3.0 m is the focal length
From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so
q = -2.0 m
This can also be verified by using the mirror equation:
B) Upright and virtual
As we see from the picture, the image is upright, since it has same orientation as the object.
Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,
- An image is said to be real if it is on the same side of the object
- An image is said to be virtual if it is on the opposite side of the mirror
Therefore, this means that the image is virtual.
Answer:
Explanation:
The form of Newton's 2nd Law that we use for this is:
F - f = ma where F is the Force pulling the mass down the ramp forward, f is the friction trying to keep it from moving forward, m is the mass and a is the acceleration (and our unknown).
We know mass and we can find f, but we don't have F. But we can solve for that by rewriting our main equation to reflect F:
That's everything we need.
w is weight: 6.0(9.8). Filling in:
6.0(9.8)sin20 - .15(6.0)(9.8) = 6.0a and
2.0 × 10¹ - 8.8 = 6.0a and
11 = 6.0a so
a = 1.8 m/s/s