the friction force provided by the brakes is 30000 N.
<h3>What is friction force?</h3>
Friction force is the force that opposes the motion between two bodies in contact.
To calculate the average friction force provided by the brakes, we apply the formula below.
Formula:
- K.E = F'd............. Equation 1
Where:
- K.E = Kinetic energy of the train
- F' = Friction force provided by the brakes
- d = distance
Make F' the subject of the equation
- F' = K.E/d............ Equation 2
From the question,
Given:
Substitute these values into equation 2
- F' = (8.1 ×10⁶)/270
- F' = 30000 N
Hence, the friction force provided by the brakes is 30000 N
Learn more about friction force here: brainly.com/question/13680415
Answer: Friction
Explanation:
Friction and the normal force would be the two initial forces to overcome.
Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N
Explanation:
- Acceleration is the rate of change of velocity.
- It is given by the equation, a = change in velocity/time
Here, velocity changes from 0 to 27 m/s and time = 8
⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²
- Force is calculated by the equation, F = Mass × Acceleration
- This is based on Newton's second law of motion.
Here, mass of the car = 1500 kg and a = 3.375 m/s²
⇒ Force = 1500 × 3.375 = 5062.5 N
Answer:
1st statement is true
Explanation:
Here statement 1 is correct
Let think about it, if you push down the bar then you are lifting your weight off the pedals.
Obviously, this question does not take into account of racing bikes with straps on pedals, where you would push on one side and pull on the other to match your legs are doing, with straps your other leg can pull pedals upward.
Answer:
Explanation:
The initial velocity, u, of the car=15m/s
The final velocity, v, of the car =0m/s
Time, t, taken for the car to come to a stop=5s
Acceleration is calculated by,
By substitution,
The negative sign implies that the car has decelerated.
