All categories

2 years ago

What is the weight of a 1-kilogram brick resting on a table?

Physics

1 answer:

MakcuM [25]2 years ago

5 0

Answer:

The weight if the block is 10Newtons

Explanation:

The weight of any object is quantity of matter the object contains and it is always acting downwards on such body. This shows that the object is under the influence of gravity.

The weight of an object is calculated as mass of the object × its acceleration due to gravity

W = mg

Give the mass of the brick to be 1kg

g is the acceleration due to gravity = 10m/s²

Weight of the object = 1 × 10

= 10kgm/s² or 10Newtons

You might be interested in

Momentum usually has the symbol p It is a vector, What is the correct way to

Nadya [2.5K]

Answer:

Add an arrow above the symbol p to show it is a vector. Sometimes it is italicized in textbooks.

Explanation:

6 0

2 years ago

Which band is the smallest within the electromagnetic spectrum?

padilas [110]

A) visible light because it just makes since

6 0

2 years ago

Read 2 more answers

A long iron bar lies along the x-axis and has current of I = 16.4 A running through it in the +x-direction. The bar is in the pr

Gre4nikov [31]

Answer:

B = 8.0487mT

Explanation:

To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,

The magnetic force is given by the formula

$F =BILsin\theta$

Where,

B = Magnetic Field

I = Current

L = Length

$\theta =$ Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees

According to our data we have that

I = 16.4A

F = 0.132N/m

As we know our equation must be modificated to Force per length unit, that is

$\frac{F}{L} = BI sin(90)$

Replacing the values we have that

$0.132 = 16.4 (1) B$

Solving for B,

$B = \frac{0.132}{16.4}$

$B = 8.0487mT$

8 0

2 years ago

Convert the following: 52 miles/hour to meters/second

Komok [63]

Answer:

23.246 metres per second

Explanation:

divide the speed value by 2.237

5 0

2 years ago

Calculate the moment of inertia of a skater given the following information. The skater with arms extended is approximately a cy

Bad White [126]

Answer:

The moment of inertia of a skater is : $I= 2.343 kgm^{2}$

Explanation:

we can use parallel theorem to find the moment of inertia of a skater.

Arm extended cylinder mass: $M= 52.5 kg$

Radius: $R= 0.110 m$

Length: $L= 0.900 m$

and $m=3.75 kg$

$I=\frac{1}{2} MR^{2} +[\frac{1}{2} mL^{2} +m(R+\frac{L}{2} )^{2} ]$

$I=\frac{1}{2} (52.5)(0.110)^{2} +[\frac{1}{12} (3.75)(0.900)^{2} +3.75(0.110+\frac{0.900}{2} )^{2} ]$

$I=2.343 kgm^{2}$

4 0

2 years ago