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notka56 [123]
2 years ago
9

Why might surface mining be less risky for miners than underground mining?

Physics
2 answers:
Marat540 [252]2 years ago
7 0

Answer:

Destruction of land, mine explosions, collapses and flooding surface subsidence,surface heaps

Explanation:

Surface mining might be  less risky for miners than underground mining because of the following

1. Underground mining is more expensive than surface mining.It takes more time and energy to mine for coal in the underground

2. Destruction of land surfaces: Underground mining actually leads to the damage to landscape. The lands change form and topography due to the mining activities.

3. Surface subsidence,

4.Abandoned shafts and extensive surface spoil heaps,

5.Explosions: There is what is known as the triangle of fire. For a fire outbreak, there must be oxydant. fuel and ignition. Once these three are in place, an explosion can occur which can lead to loss of lives and equipments etc.

6. Collapses:  Landslides might occur

due to tampering with the earth's layer during underground mining activities

7. Flooding: During underground mining, The table water can be be disrupted which might lead to flooding

aev [14]2 years ago
6 0
Surface miners work aboveground. (Apex) ^-^

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A snowball picks up speed as it rolls down the mountain.<em> (D)</em>

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A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction
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The coefficient of friction between the road and the car's tire is determined as 0.78.

<h3>Acceleration of the car</h3>

The acceleration of the car is calculated as follows;

v² = u² - 2as

0 = u² - 2as

a = u²/2s

where;

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a = 7.72 m/s²

<h3>Coefficient of friction</h3>

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1 year ago
The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?​
Simora [160]

Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{L}.

<h3>This case</h3>

In this case, you have:

  • number of moles= 70 g×\frac{1 mole}{98 g}= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
  • volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.7143 moles}{0.28 L}

Solving:

<u><em>Molarity= 2.5510 </em></u>\frac{moles}{L}

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

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