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evablogger [386]
3 years ago
7

Excluded values for y=5/(6x-72) (the / is a fraction so its 5 over 6x)

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
The denominator cannot equal zero. Set the expression on the denominator = to zero to find the value that must be excluded.
6x - 72 = 0
add 72 to both sides
6x = 72
Divide both sides by 6
x = 9
The excluded value is 9.
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