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Bess [88]
3 years ago
12

Hi, i need help with a calculus question involving limits. Could you explain how to solve this?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

In order to solve this exercise, you have to know the limit that defines the constant e:

\displaystyle \lim_{n\to\infty} \left(1+\frac{1}{n}\right)^n=e

With this limit in mind, we can perform the following variable change:

y=\dfrac{1}{x}

With this new variable, we have

x\to 0 \implies \frac{1}{x}=y\to\infty,\quad x = \dfrac{1}{y},\quad \dfrac{1}{x}=y

Substituting these pieces one by one, we have

\displaystyle \lim_{x\to 0}\left(1+x\right)^\frac{1}{x} = \lim_{y\to\infty}\left(1+\frac{1}{y}\right)^y

and this is the limit that defines e.

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5x + 13y = 232

12x + 7y = 218

For each choice:

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- 65x - 169y = - 3016

84x + 49y = 1526

Can not eliminate x and y.

b) The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. So we have

35x  + 91 y = 1624

156x + 91y = 2834

Can not eliminate x and y if we ADD.

<em>(If we subtract, this is Yes)</em>

<em></em>

c) The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

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The answer is YES

d) The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

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144x + 84y = 2616

Can not eliminate x and y

The final answer is C

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4 years ago
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