Which of the following will increase the rate of disolving?

Which of the following fractions can be used in the conversion of 32 m3 to the unit mm3?

guajiro [1.7K]

In order to covert a unit, you must know certain number of conversions. In here, the conversion is in unit of length. One meter is equal to 1000 meter. So if it is in cubic form, then the answer of one meter cube is also equal to 1000 cube. Then,

32 m³ (1000 mm/1m)³
or
32 m³ (1000³ mm³/1 m³)
= 3.2 x 10¹⁰ mm³

3 0

3 years ago

Plzz help me well mark brainliest if you are correct

tia_tia [17]

Answer:

A. non renewable energy sources cannot be used over again and renewable energy sources can be used again

6 0

3 years ago

Read 2 more answers

1. Take the reaction: NH3 + O2 + NO + H2O. In an experiment, 3.25g of NH3 are allowed

Rudiy27

Answer:

5.74g of NO

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

4NH3 + 5O2 —> 4NO + 6H2O

Step 2:

Determination of the masses of NH3 and O2 that reacted and the mass of NO produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g

Molar Mass of NO = 14 + 16 = 30g/mol

Mass of NO from the balanced equation = 4 x 30 = 120g

From the balanced equation above,

68g of NH3 reacted with 160g of O2 to produce 120g of NO.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting because it will be used to calculate the maximum yield of the reaction. This is illustrated below:

From the balanced equation above,

68g of NH3 reacted with 160g of O2.

Therefore, 3.25g of NH3 will react with = (3.25 x 160)/68 = 7.65g of O2.

From the simple illustration above, we can see that lesser mass of O2 is needed to react with 3.25g of NH3. Therefore, NH3 is the limiting reactant while O2 is the excess reactant.

Step 4:

Determination of the mass of NO produced from the reaction.

In this case the limiting reactant will be used because all of it were used in the reaction.

The limiting reactant is NH3.

From the balanced equation above,

68g of NH3 reacted to produce 120g of NO.

Therefore, 3.25g of NH3 will react to produce = (3.25 x 120)/68 = 5.74g of NO.

From the calculations made above, 5.74g of NO is produced.

4 0

3 years ago

This equation is not balanced. Click on the coefficient we should change first. help ASAP

horrorfan [7]