Answer:
hi
Explanation:
I'm just figuring this out what am I doing
Answer:
![m_{H_2O}=0.676gH_2O](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D0.676gH_2O)
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:
![CH_4+2O_2\rightarrow CO_2+2H_2O](https://tex.z-dn.net/?f=CH_4%2B2O_2%5Crightarrow%20CO_2%2B2H_2O)
Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:
![0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O](https://tex.z-dn.net/?f=0.963%20gCH_4%2A%5Cfrac%7B1molCH_4%7D%7B16gCH_4%7D%2A%5Cfrac%7B2molH_2O%7D%7B1molCH_4%7D%20%20%3D0.120molH_2O%5C%5C%5C%5C1.2gO_2%2A%5Cfrac%7B1molO_2%7D%7B32gO_2%7D%2A%5Cfrac%7B2molH_2O%7D%7B2molO_2%7D%20%20%3D0.0375molH_2O)
Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:
![m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O](https://tex.z-dn.net/?f=m_%7BH_2O%7D%3D0.0375molH_2O%5Cfrac%7B18.02gH_2O%7D%7B1molH_2O%7D%3D0.676gH_2O)
Regards!
Answer:
Option A, The organism experiences a disruption in homeostasis.
Explanation:
When a pathogen enters the organism’s body, it disrupts its homeostasis. There are several receptors in the body that are responsible for maintaining the stability of the body through negative feedback loop.
A foreign element attaches to the surface of these receptors and hence disrupts their attachment with the probable substance necessary for the regulation of essential body function.
Thus, the temperature regulation get s impaired, hormonal imbalances occur, feeding system disturbs etc.
Hence, option A is correct
Answer:
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Answer:
The atomic mass of Si-30 is 29.955 amu
Explanation:
Step 1: Data given
Si-28 has an atomic mass of 27.9769 amu and a natural abundance of 92.2 %
Si-29 has an atomic mass of 28.9765 amu and a natural abundance of 4.67%
The atomic mass of Si is 28.0855 amu
Step 2: Calculate natural abundance of Si-30
100% - 92.2 % - 4.67% = 3.13 %
0.922 * 27.9769 + 0.0467 * 28.9765 + 0.0313* X = 28.0855
27.14790435 + 0.0313X = 28.0855
0.0313X = 0.93760
X = 29.955 amu
The atomic mass of Si-30 is 29.955 amu