Answer:

Explanation:
The half-cell reduction potentials are
Ag⁺(aq) + e⁻ ⇌ Ag(s) E° = 0.7996 V
Fe²⁺(aq) + 2e⁻ ⇌ Fe(s) E° = -0.447 V
To create a spontaneous voltaic cell, we reverse the half-reaction with the more negative half-cell potential.
The anode is the electrode at which oxidation occurs.
The equation for the oxidation half-reaction is

Answer:
Kj/mol
Its an endothermic reaction
Explanation:
Enthalpy can be evaluated by using following formula -

where
q is the enthalpy or change in internal energy
m is the mass in kg
c is the specific heat
and
is the change in temperature
Mass of HCl is equal to
g/mol
or
Mass of HCl is equal to
Kg/mol
Substituting the given values in above equation, we get-

Kj/mol
Enthalpy is positive thus it is an endothermic reaction
The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.
The average atomic mass of Te can be calculated as follows:

Where:
m: is the mass
%: is the abundance percent
Knowing all the masses and abundance values, we have:

To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>

Therefore, the average atomic mass of tellurium is 127.723 amu.
You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults
I hope it helps you!
Answer:
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Explanation: