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4 years ago

Calculate the entropy change when 4.31 g of H2 reacts with O2 according to the reaction

Chemistry

1 answer:

Mazyrski [523]4 years ago

8 0

Answer:

Explanation:

ΔG = Δ H - T ΔS

Given , ΔG = -237.2 kJ / mol

Δ H = - 285.8 kJ / mol

T = 298

Putting the values in the equation

-237.2 = - 285.8 - 298 x ΔS

ΔS = .163 kJ / mole K

moles of water formed = 4.31 / 2 = 2.155

entropy change required = 2.155 x .163 kJ / K

= 351.26 J / K .

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A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrea

Maksim231197 [3]

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

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2 years ago

One of these notations represents the definition of one mole. That is

just olya [345]

Answer:

6.02*10^23

Explanation:

This is the number for one mole. Just like one dozen = 12, one mole = 6.02*10^23.

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4 years ago

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4 years ago

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What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4

valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

$k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}$

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

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3 years ago

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The answer would be Force

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3 years ago

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