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3 years ago

Calculate the entropy change when 4.31 g of H2 reacts with O2 according to the reaction

Chemistry

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

Explanation:

ΔG = Δ H - T ΔS

Given , ΔG = -237.2 kJ / mol

Δ H = - 285.8 kJ / mol

T = 298

Putting the values in the equation

-237.2 = - 285.8 - 298 x ΔS

ΔS = .163 kJ / mole K

moles of water formed = 4.31 / 2 = 2.155

entropy change required = 2.155 x .163 kJ / K

= 351.26 J / K .

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How many significant digits are 6.3590x10 7 mm

Svet_ta [14]

If you go by the decimal there should be 5 significant digits because 0 is a trailing zero and matters since it comes after a decimal. however if you do

6.3590 x 10 ^7 = 63590000 then you would only have 4 significant digits because there is no longer a decimal to make the zero after the 9, significant.

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3 years ago

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Which of the following hydrocarbons has a double bond in its carbon skeleton?1) C3H82) C2H63) CH44) C2H45) C2H2

Kipish [7]

Answer:

C₂H₄ (option number 4)

Explanation:

A hydrocarbon with a double bond in its carbon skeleton is an alkene and has the general form:

$C_nH_{2n}$ .

This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) C₃H₈:

In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.

2) C₂H₆

For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.

3) CH₄

Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane

4) C₂H₄

Hydrogen atoms: 2 × 2 = 4. This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.

The chemical formula may be writen as CH₂ = CH₂, to show the double bond.

So, this is the correct answer.

5) C₂H₂

Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.

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3 years ago

Based on the size and shape of the clasts in the sedimentary rock shown in the image, which classification would geologists mos

Veronika [31]

Answer:

D. Brecci

The pattern of the rock below resembles the distinct pattern of brecci.

The pattern of conglomerate usually appears to be more round peices in the rock. The pattern of brecci has a more shard like appearance.

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3 years ago

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If an unknown sample contains 39.04% sulfuric acid by mass, then a 0.9368 g of that sample would require _____ mL of 0.2389 M Na

bonufazy [111]

Answer:

A) 31.22

Explanation:

The reaction of sulfuric acid with NaOH is:

H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O

To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.

Moles H₂SO₄ (Molar mass: 98.08g/mol):

0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =

3.7289x10⁻³moles H₂SO₄

And moles of NaOH that you require to neutralize the acid are:

3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =

7.4578x10⁻³ moles NaOH

Using a 0.2389M NaOH solution:

7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL

Right answer is:

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Vilka [71]

I think variation.... have a great day

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