Calculate the entropy change when 4.31 g of H2 reacts with O2 according to the reaction
1 answer:
Answer:
Explanation:
ΔG = Δ H - T ΔS
Given , ΔG = -237.2 kJ / mol
Δ H = - 285.8 kJ / mol
T = 298
Putting the values in the equation
-237.2 = - 285.8 - 298 x ΔS
ΔS = .163 kJ / mole K
moles of water formed = 4.31 / 2 = 2.155
entropy change required = 2.155 x .163 kJ / K
= 351.26 J / K .
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