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Lerok [7]
3 years ago
12

Calculate the entropy change when 4.31 g of H2 reacts with O2 according to the reaction

Chemistry
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

Explanation:

ΔG  =  Δ H - T ΔS

Given , ΔG = -237.2 kJ / mol

Δ H = - 285.8 kJ / mol

T = 298

Putting the values in the equation

-237.2 = - 285.8 - 298 x ΔS

ΔS  = .163 kJ / mole K

moles of water formed = 4.31 / 2 = 2.155

entropy change required = 2.155 x .163 kJ / K

= 351.26 J / K .

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motikmotik

Answer:

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium

N_2 (g) + 3 H_2 (g)\rightleftharpoons 2 NH_3 (g) + heat

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

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