)-(−)-Carvone is responsible for the characteristic
minty odor and flavor of spearmint oil, and it can also serve as a
useful chiral starting material for organic synthesis. A
carbon-carbon π bond is normally nucleophilic, but one of the two
carbon-carbon π bonds in (R)-(−)-carvone is actually
electrophilic!

Draw resonance structures of (R)-(−)-carvone.
Do not draw resonance and curved arrows in your answer. Include
formal charges and lone pais in yo
This question should have choices. These are the choices: A.) chemical properties of solute
the B.) type and polarity of the solvent C.)
the temperature D.) concentration of solute
A and B are related and is a huge factor in determining how well substances dissolve. C is again another key factor. Since the more we increase the temperature, for most substances, dissolution also increases. D would have to be the answer.
Answer:
~26 atoms of sulfur
Explanation:
When working problems involving equations I find it helpful to works through moles because it relates to the coefficients of balanced equation by linear ratio. In other words, convert data to moles, solve by ratio and convert results to desired dimensions. In this case Atoms of Sulfur.
Given: 52 atoms K = 52 atoms/6.02 x 10²³atoms K/mole K = 9.64 x 10⁻²³ mole K atoms.
Using ratios in given equation 4K + 2S => 2K₂S
Says
4 moles K reacts with 2 moles Sulfur, then
8.64 x 10⁻²³ mole K reacts with X moles Sulfur
Set up ratio:
(4 moles K) / (8.64 x 10⁻²³ moles K) = (2 moles S) / X
Solve for X => X = (2 moles S x 8.64 x 10⁻²³ mole K) / 4 mole K = 4.32 x 10⁻²³ mole S used
Converting moles S to atoms S, multiply by Avogadro's Number ...
Atoms S used = 4.32 x 10⁻²³ mole S used x 6.02 x 10²³ Atoms S / mole S
=> 26.0064 Atoms S ≈ 26 Atoms Sulfur used.
Note: This is a reasonable answer in that the balanced equation given indicates that half the number moles S reacts with K. So, one can conclude that half the number of potassium atoms would indicate the number of sulfur atoms needed. test => ¹/₂(52) = 26 atoms S.
Answer:
46.9mg of oxygen
Explanation:
From Henry's law,
Concentration of oxygen (C) = Henry's constant (K) × partial pressure of oxygen in air (p)
K = 1.3×10^-3M/atm O2, p = mole fraction of oxygen in air × pressure of air = 0.21×1.08atm = 0.2268atm
C = K×p = 1.3×10^-3 × 0.2268 = 0.00029484M of O2
Concentration (C) = number of moles of oxygen (n)/volume of water (V)
Volume of water (V) = 4.97L
n = CV = 0.00029484 × 4.97 = 0.001465mole
number of moles (n) = mass of O2/MW of O2
mass of O2 = number of moles of O2 × MW of O2 = 0.001465mole × 32g/mole = 0.0469g = 0.0469×1000mg = 46.9mg (to three significant figures)
What i'm English i do not know what are you talking about