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3 years ago

If the ph of a solution is decreased from ph 8 to ph 6 it means that the

2 answers:

8 0

If the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions in the solution has been increased while the concentration of OH ions have been decreased.

<h2>Further Explanation: </h2><h3>pH and pOH </h3>

pH and pOH measures the acidity or alkalinity of a substance.
pH is the measure hydrogen ion concentration in a substance while pOH measures the concentration of hydroxyl ions.

<h3>Acids and bases </h3><h3>Acids </h3>

Acids are substances that react with bases to form salt and water as the only products.
Acids have a pH less than 7, with strong acids having a pH range of 1-3 while weak acids have a pH range of 4-6.
The pOH of acids on the other hand is greater than 7.

<h3>Bases</h3>

Bases are substances that react with acids to form salt and water as the only product.
Bases have a pH greater than 7, with strong bases having a pH range of 12-14 and weak bases having a pH range of 8-11.
Bases have a pOH less than 7.

<h3>Calculation of pH and pOH </h3>

pH is calculated as the negative logarithm of hydrogen ion concentration.

That is;

pH = -Log [H+]

pOH on the other hand is calculated as the negative logarithm of hydroxyl ion concentration.

That is;

pOH =-Log[OH-]

Additionally;

pH + pOH = 14

Keywords: Acids, bases, pH, pOH

<h3>Learn more about:</h3>

pH :brainly.com/question/10951922
pOH : brainly.com/question/10951922
Example of a question on pH: brainly.com/question/10951922
Example of a question on pOH: brainly.com/question/10951922

Level; High school

Subject: Chemistry

Topic: Acids and bases

Sub-topic; pH and pOH

saw5 [17]3 years ago

5 0

Explanation:

Relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

So, it means that an increase in the value of pH will show that there occurs a decrease in concentration of hydrogen ions.

Therefore, the solution becomes basic in nature.

On the other hand, a decrease in the value of pH will show that there occurs an increase in the concentration of hydrogen ions.

Therefore, the solution becomes more acidic in nature.

Hence, if the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions has increased in the solution.

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The fertilizer ammonium sulfate, (NH4)2SO4, is prepared by the reaction between ammonia (NH3) and sulfuric acid:

kumpel [21]

The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is 6.18 * 10⁴ Kg of ammonia.

<h3>What mass in kilograms of ammonia are required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄?</h3>

The mass of ammonia required to produce 2.40 × 10⁵ kg of (NH₄)₂SO₄ is determined from the mole ratio of the reaction.

The mole ratio of the reaction is obtained from the balanced equation of the reaction given below:

2NH₃(g) + H₂SO₄(aq) → (NH₄)₂SO₄(aq)

Mole ratio of NH₃ and (NH₄)₂SO₄ is 2: 1

Mass of 2 moles of ammonia = 2 * 17 = 34 g

Mass of 1 mole of (NH₄)₂SO₄ = 132 g

Mass of ammonia required = 34/132 * 2.40 × 10⁵ kg

Mass of ammonia required = 6.18 * 10⁴ Kg of ammonia.

In conclusion, the mole ratio is used to determine the mass of ammonia required.

Learn more about mole ratio at: brainly.com/question/19099163

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4 0

2 years ago

Given the enthalpies of reaction

Tju [1.3M]

2SO₂+O₂⇒2SO₃ ΔH=-197 kJ

<h3>Further explanation</h3>

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways

Reaction

2SO₂+O₂⇒2SO₃

Given :

1. S(s)+O₂(g)→SO₂(g) ΔH = -297 kJ

Reverse

SO₂(g) ⇒S(s)+O₂(g ΔH = +297 kJ (sign change to +) x 2

2SO₂(g) ⇒2S(s)+2O₂(g ΔH = +594 kJ

2.2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ

Add both reactions and remove/subtract the same compound for different sides

1. 2SO₂(g) ⇒2S(s)+2O₂(g) ΔH = +594 kJ

2.2S(s)+3O₂(g)→2SO₃(g) ΔH=-791kJ

--------------------------------------------------------+

2SO₂+O₂⇒2SO₃ ΔH=-197 kJ

5 0

3 years ago

A throat spray is 1.40% by mass Phenol, C6H5OH in water. If the solution has a density of 0.9956 g/ml, calculate the molarity of

myrzilka [38]

<u>Answer:</u> The molarity of solution is 1.08 M

<u>Explanation:</u>

We are given:

(m/m) of phenol = 1.40 %

This means that 1.40 g of phenol is present in 100 g of solution.

To calculate volume of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 0.9956 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

$0.9956g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=100.442mL$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (phenol) = 1.40 g

Molar mass of phenol = 94.11 g/mol

Volume of solution = 100.442 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.40g\times 1000}{94.11g/mol\times 100.442mL}\\\\\text{Molarity of solution}=0.15M$

Hence, the molarity of solution is 0.15 M

8 0

3 years ago

Substance X is a compound containing 632mg of manganese and 368mg of oxygen. Substance X is shown

defon

The empirical formula : MnO₂.

<h3>Further explanation</h3>

Given

632mg of manganese(Mn) = 0.632 g

368mg of oxygen(O) = 0.368 g

M Mn = 55

M O = 16

Required

The empirical formula

Solution

You didn't include the pictures, but the steps for finding the empirical formula are generally the same

Find mol(mass : atomic mass)

Mn : 0.632 : 55 = 0.0115

O : 0.368 : 16 =0.023

Divide by the smallest mol(Mn=0.0115)

Mn : O =

$\tt \dfrac{0.0115}{0.0115}\div \dfrac{0.023}{0.0115}=1\div 2$

The empirical formula : MnO₂

8 0

3 years ago

Which of the following is a base?<br> OHBr<br> OHCI<br> ОNaOH<br> СНІ

Paladinen [302]

Answer:

NaOH

Explanation:

Sodium hydroxide is a base because it dissociate into hydroxl ion when dissolved in water .

8 0

3 years ago