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kifflom [539]
3 years ago
6

The oxygen side of a water molecule is _____.

Chemistry
1 answer:
tatiyna3 years ago
4 0
The correct answer would be “slightly negative”.
You might be interested in
An object has a gravitational potential energy that is 800 Joules. Its
olya-2409 [2.1K]

Answer:

36.28 kg

Explanation:

Given data:

Gravitational potential energy of object = 800 J

Height from ground = 2.245 m

Mass of object = ?

Solution:

Formula:

P.E = mgh

g =acceleration due to gravity =  9.8 m/s²

by putting values,

800 J = m× 9.8 m/s² ×2.25 m

J = kgm²/s²

800 kgm²/s² = m× 22.05 m²/s²

m = 800 kgm²/s² /22.05 m²/s²

m = 36.28 kg

6 0
2 years ago
If the mass of a material is 91 grams and the volume of the material is 20 cm3, what would the density of the material be?
AlekseyPX
Use the formula Density=Mass/Volume
8 0
3 years ago
A solution is prepared by mixing 25.0 g H2O and 25.0 g C2H5OH. Determine the mole fractions of each substance.
Veronika [31]

Answer:

Mole fraction H₂O → 0.72

Mole fraction C₂H₅OH → 0.28

Explanation:

By the mass of the two elements in the solution, we determine the moles of each:

25 g . 1 mol/ 18g = 1.39 moles of water (solute)

25 g . 1 mol / 46 g = 0.543 moles of ethanol (solvent)

Mole fraction solute = Moles of solute / Total moles

Mole fraction solvent = Moles of solvent / Total moles

Total moles = Moles of solute + Moles of solvent

1.39 moles of solute + 0.543 moles of solvent = 1.933 moles → Total moles

Mole fraction H₂O = 1.39 / 1.933 → 0.72

Mole fraction C₂H₅OH= 0.543 / 1.933 → 0.28

Remember that sum of mole fractions = 1

8 0
2 years ago
Read 2 more answers
A bowling ball rests on the floor. The bowling ball is given a push.
lyudmila [28]

Answer:

A. It will move.

8 0
2 years ago
A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d
g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of Ba(OH)_2 as:-

Mass = 51.24 g

Molar mass of Ba(OH)_2 = 171.34 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{51.24\ g}{171.34\ g/mol}

Moles= 0.2991\ mol

Volume = 1.20 L

The expression for the molarity is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M

Thus,

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=0.100\ M

Volume_{working\ solution}=1\ L

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=0.24925\ M

So,  

0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

6 0
3 years ago
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