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Diano4ka-milaya [45]
3 years ago
12

True or False: The order of the General Steps in Building Math Models is:

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0
The correct answer is false the order should be 

Step 1
Step 3
Step 5
Step 2 
Step 6
Step 4 
Step 7 
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Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
CAN YOU HELP ME PLEASE
mamaluj [8]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Who could help me solve this?<br><br> Y=log x<br><br> If y=10, then what is x?
Viktor [21]

Step-by-step explanation:

y = log \: x \\  \\  \therefore \: 10 = log \: x \\ \therefore \:  {e}^{10}  = x \\  \\  \therefore \: x = {e}^{10}  \\

6 0
4 years ago
Can someone please help !!!!!
Katen [24]
I'm I am so sorry I haven't done this hey sorry
8 0
3 years ago
PTN is adjacent to: <br><br> A. QTR<br> B. PTS<br> C. RTS<br> D. QTS
VikaD [51]

Answer:

B

Step-by-step explanation:

Adjacent means sharing a common edge or leg so here PTN is adjacent to PTS

8 0
3 years ago
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