Answer:
The percent ionization is 0,16%
Explanation:
The percent ionization is defined as the number of ions that exist in a substance.
![PI=\frac{[A-]}{[HA]} x100](https://tex.z-dn.net/?f=PI%3D%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D%20x100)
First, we find the [A-] using the ka equation
HA ⇄ 
[H+] = [A-]
![Ka=\frac{[H+][A-]}{[HA]}\\ \\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D%5C%5C%20%5C%5C)
since the ionization constant is very small we can assume that the final concentration of [HA] is the same
![Ka=\frac{[H+]^{2} }{[HA]} \\\\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5E%7B2%7D%20%7D%7B%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+]=\sqrt[2]{Ka.[HA]} \\\\](https://tex.z-dn.net/?f=%5BH%2B%5D%3D%5Csqrt%5B2%5D%7BKa.%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+] =\sqrt{(2,610^{-7} )(0,1)} = 1,61210^{-4}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%5Csqrt%7B%282%2C610%5E%7B-7%7D%20%29%280%2C1%29%7D%20%20%3D%201%2C61210%5E%7B-4%7D)
Now we calculate the percent ionization using these values
PI=0,16%
25 milliliters are required
50 grams salt
Volume of 50 Grams of Salt
50 Grams of Salt =
2.78 Tablespoons
8.33 Teaspoons
0.17 U.S. Cups
0.14 Imperial Cups
C, erosion. Erosion is the natural process of breaking down natural products through wind, or similar natural resources.
Answer:
Volumen C6H8O6(sln) = 2.569 L ≅ 2.6 L
Explanation:
vitamin C ≡ ascorbic acid (C6H8O6)
∴ vitamin C/daily = 75.0 mg/d
∴ molar mass C6H8O6 = 176.12 g/mol
solution:
∴ <em>C</em> C6H8O6 = 0.002486 mol/L
⇒ ppm C6H8O6 = (0.002486 mol/L)*(176.12 g/mol)*(1000 mg/g)
⇒ ppm C6H8O6 = 437.834 mg/L
for a 15.0 day:
⇒ Volume C6H8O6(sln) = (75.0 mg/d)*(L/437.834 mg)*(15.0 d)
⇒ Volume C6H8O6(sln) = 2.569 L
