Answer:
There are 6.022 × 10 23 O atoms in a mole of O atoms. There are 6.022 × 10 23 O 2 molecules in a mole of . Since you have 2 oxygen atoms in one molecule, there are 2 × 6.022 × 10 23 O atoms in a mole of . A 'mole' is not short for a 'molecule
Explanation:
The formula would be MgMn2O8
Answer:
<h3>The answer is 27.80 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 87.3 g
density = 3.14 g/mL
We have

We have the final answer as
<h3>27.80 mL</h3>
Hope this helps you
2NBr₃ + 3NaOH = N₂ + 3HOBr + 3NaBr
40 mol 48 mol
NBr₃:NaOH = 2:3
40:48 = 2:2.4 = 2.5:3
NBr₃ is the excess reactant