Answer:
There is 78.25g NaHCO3 required
Explanation:
Step 1: Balance the equation
2 NaHCO3 → Na2CO3 + CO2 + H20
For 2 moles of NaHCO3 consumed, there is produced 1 mole of Na2CO3, 1 mole of CO2 and 1 mole of H2O.
Step 2: calculating moles of CO2
mass of Co2 = 20.5g
Molar mass of CO2 = 44.01 g/mole
moles of CO2 = 20.5 / 44.01 = 0.4658 moles
Step 3: Calculating moles of NaHCO3
Since we have for 1 mole CO2 produced, there is 2 moles of NaHCO3 consumed.
To calculate number of moles of NaHCO3, we have to multiply the number of moles of CO2, by 2.
⇒ 0.4658 x2 = 0.9316 moles
Step 4: Calculating the mass of NaHCO3
mass of NaHCO3 = moles of NaHCO3 x Molar mass of NaHCO3
mass = 0.9316 moles x 84g/ mole = 78.25g NaHCO3
There is 78.25g NaHCO3 required
