1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gennadij [26K]
3 years ago
15

Help with question 19 please

Physics
1 answer:
juin [17]3 years ago
6 0

Answer:

4.2m/s

Explanation:

Now the velocity or speed initiated by the 200g mass at 7.0m/s is related by the formula;

V=ω×r ; ω is the angular velocity

r is the distance

Note that;

ω = √k/m. ; where K is the Force constant of the spring.

m is the mass

We see from the two expressions that v will only change with r if the spring constant and mass stays the same.

Hence we can rewrite the equation of v for two pairs of velocity V1 , V2 and distance r1 , r2 as;

V1/r1 = V2/R2

If V1=7.0m/s , r1=25cm= 0.25m

V2=? r2 = 15cm = 0.15m

Hence we can calculate V2 and is;

V2 = V1 × R2/ R1

V2 = 7 × 0.15 / 0.25= 4.2m/s

You might be interested in
the idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse
Finger [1]

Forward thrust has positive values and reverse thrust has negative values.

Thrust is a sudden push or pull in a certain direction.

a)

Flight speed u = 150 km/h

1 km/h = \frac{1}{3.6} km/s

therefore, 150 km/h =  41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (150 - 41.67)

T = 5416.67 N

Therefore, the value of forward thrust is 5416.67 N.

b)

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,

thus thrust equation is:

T = m_{exhaust} * U_{exhaust} - U_{flight}

T = 50 * (0 - 41.67)

T = -2083.5 N

Therefore, the thrust force T is -2083.5 N in the reverse direction.

c)

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero becauseU_{exhaust} = U_{flight} = 0\\

T = 0

Therefore, there is no difference in two velocities in x direction.

The given question is incomplete, the complete question is,

"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.

a. What is the forward thrust of this engine?

b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?

c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"

To know more about thrust,

brainly.com/question/14552836

#SPJ1

3 0
1 year ago
A swimmer, capable of swimming at a speed of 1.0 m/s in still water (i.e., the swimmer can swim with a speed of 1.0 m/s relative
Vesnalui [34]
If the current takes him downstream we must find the resultant vector of the velocities: V res= \sqrt{1^{2}+0.91^{2}  } = \sqrt{1.8281}= 1.3520747 Then if the river is 3000 m-wide the swimmer will have to pass:
 1.3520747 · 300 = 4056.14 m                t = 4056.14 m : 1 m/s
a ) It takes 4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.  
b ) 0.91 · 3000 = 2730 m
He will be 2730 m downstream.
5 0
3 years ago
A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
3 years ago
Plz answer brainliest if right!
AleksandrR [38]

Answer: it is D. it is the only possible answer. use the process of elimination. which answers make sense?

4 0
3 years ago
In the picture of the atom above, what subatomic particle does the letter A represent?
ra1l [238]

Answer:

Electron

Explanation:

In the picture, the letter A is pointing to an electron.

4 0
3 years ago
Other questions:
  • Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
    12·1 answer
  • Is the following true or false?
    10·2 answers
  • 1. what are valence electrons?
    11·2 answers
  • Endocrine system immune response
    13·1 answer
  • Calculate the volume of the metal required to make a hemisperical bowl with internal and external radii 8.4cm and 9.1cm respecti
    9·1 answer
  • A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10
    13·1 answer
  • Pls give me an example of newton's 1 ,2 ,3 law of motion pls this is due tomorrow
    10·1 answer
  • TIMED! URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!!
    11·2 answers
  • We can see light move with our bare eyes true or false​
    15·2 answers
  • A bullet travels at 850 m/s. How long will it take a bullet to go 1000 m?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!