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Gennadij [26K]
3 years ago
15

Help with question 19 please

Physics
1 answer:
juin [17]3 years ago
6 0

Answer:

4.2m/s

Explanation:

Now the velocity or speed initiated by the 200g mass at 7.0m/s is related by the formula;

V=ω×r ; ω is the angular velocity

r is the distance

Note that;

ω = √k/m. ; where K is the Force constant of the spring.

m is the mass

We see from the two expressions that v will only change with r if the spring constant and mass stays the same.

Hence we can rewrite the equation of v for two pairs of velocity V1 , V2 and distance r1 , r2 as;

V1/r1 = V2/R2

If V1=7.0m/s , r1=25cm= 0.25m

V2=? r2 = 15cm = 0.15m

Hence we can calculate V2 and is;

V2 = V1 × R2/ R1

V2 = 7 × 0.15 / 0.25= 4.2m/s

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Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

d=ut+\dfrac{1}{2}at^2

d=10\times 8+\dfrac{1}{2}\times 3.5\times 8^2\\\\d=192\ m

So, the distance travelled by the object is 192 meters.

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Explanation:

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Set the radius to 2.0 m and the velocity to 1.0 m/s. Keeping the radius the same, record the magnitude of centripetal accelerati
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Water enters a cylindrical tank through two pipes at rates of 250 and 100 gal/min. If the level of the water in the tank remains
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The total amount of water that enters the tank is:

250 gal/min + 100 gal/min = 350gal/min.

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v =  (80,850in^3/min)/50.24in^2 = 1609.3 in/min.

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