Answer:
time tt = 40.76 s
Explanation:
In this exercise we can find the acceleration time, the speed with which the acceleration ends and the rise and flight time
For all these calculations we can use vertical launch kinematics
The speed for maximum height is zero
v² = v₀² - 2 g y
v₀ = √ 2gy
v₀ = √ (2 9.8 980)
v₀ = 138.59 m / s
The time it takes to climb after finishing the acceleration is
v = v₀ - gt
t₁ = v₀ / g
t₁ = 138.59 / 9.8
t₁ = 14.14 s
The acceleration time is
v = v₀ + a t₂
As part of the rest the initial speed is zero
t₂ = v / a
t₂ = 138.59 / 16
t₂ = 8.66 s
The height raised at this time is
y₂ = v₀ t + ½ a t²
y₂ = 0 + ½ 16 8.66²
y₂ = 600 m
Let's look for the descent time, the height of the rocket is
y = y₂ + y₁
y = 600 + 980
y = 1580 m
y = v₀t + ½ g t²
v₀ = 0
t₃ = √ 2y / g
t₃ = √ (2 1580 / 9.8)
t₃ = 17.96 s
Total flight time is
tt = t₁ + t₂ + t₃
tt = 14.14 + 8.66 + 17.96
tt = 40.76 s
20 rev =5 sec
1sec=4rev
1rev=1/4 sec
Time period =1/4
Frequency =4
The same combination burglary/fire alarm system listed for household use can not be used in a small mercantile occupancy hence the statement is false.
<h3>What is a small mercantile occupancy?</h3>
A small mercantile occupancy refers to an area that is used for the display of certain goods. It is in short a mini commercial space.
We can not use the same combination burglary/fire alarm system listed for household in a small mercantile occupancy hence the statement is false.
Learn more about small mercantile occupancy:brainly.com/question/17866538?
Answer:
The area of the liquid surface does not affect the pressure.
Answer:
I am so sorry about that.
Explanation: