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Andrews [41]
3 years ago
8

If a car weighing 1500 kg and a Truck weighing 4000 kg are both traveling at 55 miles per hour which one will take more Force to

stop
Physics
2 answers:
patriot [66]3 years ago
5 0
The truck will require force to stop:

Force equals Mass x Acceleration (F = m * a)
Both vehicles will need to decelerate by 55 miles per hour, so the one with a greater mass, m, will require more force to stop. The truck has a mass of 4000 kg, which is greater than the car's 
padilas [110]3 years ago
3 0
The same amount of force can stop both the car and the truck. But it would take longer to stop the truck, because the truck has more mass, so the acceleration of the truck would be smaller.
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A child pulls on a wagon with a force of 75 N. If the wagon moves a total of 42 m in 3.1 min, what is the average power delivere
exis [7]

Answer:

16.96 W

Explanation:

Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

From the question,

P = (F×d)/t....................... Equation 1

Where P = power, F = force, d = distance, t = time.

Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s

Substitute these values into equation 1

P = (75×42)/186

P = 16.94 W

Hence the average power delivered by the child  = 16.96 W

4 0
3 years ago
The ________ is the maximum value or strength of the signal over time; typically this value is measured in volts.
Harrizon [31]
Peak value is what we say to the maximum value of the signal..

or rms value..root mean square value
5 0
3 years ago
a girl skateboards with a kinetic energy of 2543.2 J. if the girl and the skateboard have a total mass of 110 kg, what is her sp
zhuklara [117]
     Using the definition of kinetic energy, we have:

E_{c}= \frac{mv^2}{2}  \\ 2543.2*2=110v^2 \\ \boxed {v=6.8m/s}
6 0
3 years ago
A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and ampli
lys-0071 [83]

Answer:

(a) P_{avg} = 0.22 W

(b) P_{avg,2} = 0.056 W

Explanation:

given information:

the mass of piano wire, m = 3.00 g = 0.003 kg

tension, F = 25 N

length, l = 80 cm = 0.8 m

frequency, f = 120 Hz

amplitude, A = 1.6 mm = 0.0016 m

(a) the average power carried by the wave, P_{avg}

P_{avg} = \frac{1}{2}(√μF)ω²A²

where,

ω = 2πf = 2π120 = 754s^{-1}

μ = \frac{m}{l}

  = \frac{0.003}{0.8}

  = 0.00375 kg/m

thus,

P_{avg} = \frac{1}{2}(√(0.00375)(25))(754)²(0.0016)²

P_{avg} = 0.22 W

(b) What happens to the average power if the wave amplitude is halved.

based on the equation above, we know that the average power is proportional to the square amplitude. therefore

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{A_{2} ^{2} } }

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{(0.5A_{1} )^{2} } }

P_{avg,2} = \frac{0.22}{4}

P_{avg,2} = 0.056 W

4 0
3 years ago
What is the Mirror equation? What does it look like?
kipiarov [429]

Answer:

1/f = 1/D' + 1/D

The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (h^i) and object height (h^o). The magnification equation is stated as follows:

M= H^i/H^o = D^i/D^o

7 0
3 years ago
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