Their linear inertia is equivalent to their masses. Let the inertia of the first moose be m₁ and the second be m₂.
m₁u + m₂u = (m₁ + m₂) x 1/3 u
3m₁ + 3m₂ = m₁ + m₂
3 m₁/m₂ + 3 = m₁/m₂ + 1
m₁/m₂ = 2
The ratio of their inertias is 2
Answer:
![E=2.04\times 10^{-18}\ J](https://tex.z-dn.net/?f=E%3D2.04%5Ctimes%2010%5E%7B-18%7D%5C%20J)
Explanation:
We need to find the energy for an electron to jump from n = 1 to n = 4.
The energy in transition from 1 state to another is given by :
![E=\dfrac{-2.18\times 10^{-18}}{n^2}\ J](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B-2.18%5Ctimes%2010%5E%7B-18%7D%7D%7Bn%5E2%7D%5C%20J)
The difference in energy for n = 1 to n = 4 is:
![E=-2.18\times 10^{-18}\times (\dfrac{1}{4^2}-1)\\\\E=2.04\times 10^{-18}\ J](https://tex.z-dn.net/?f=E%3D-2.18%5Ctimes%2010%5E%7B-18%7D%5Ctimes%20%28%5Cdfrac%7B1%7D%7B4%5E2%7D-1%29%5C%5C%5C%5CE%3D2.04%5Ctimes%2010%5E%7B-18%7D%5C%20J)
So, the required energy is equal to
.
C is a non-metal and so is O. So the answer is CO
Answer choice d is correct