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Trava [24]
3 years ago
5

1:a boy 2 a girl pulling a heavy crate at the same time w/10 unite of force each.What is the net force acting on the object

Physics
1 answer:
vovangra [49]3 years ago
8 0
The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
The minimum magnitude of the net force on the box is 0 N, which will occur when the boy and the girl pull the box together in the parallel but opposite direction.
If either of them pulls at an angle from the horizontal, then the magnitude of the net force will be between 0 N and 20 N.
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30 points must be a legitimate answer and correct answer or I will report
kupik [55]

Answer:

it's C

Explanation:

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6 0
2 years ago
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What type of acceleration does an object moving with constant speed in a circular path experience?Select one:A) constant acceler
olga_2 [115]

ANSWER:

D) centripetal acceleration.

STEP-BY-STEP EXPLANATION:

When a body performs a uniform circular motion, the direction of the velocity vector changes at every instant. This variation is experienced by the linear vector, due to a force called centripetal, directed towards the center of the circumference that gives rise to the centripetal acceleration.

Therefore, the answer is centripetal acceleration.

3 0
1 year ago
If you have any questions, let me know​
klasskru [66]

Answer:

The red car would experience the greatest acceleration.

Explanation:

Newton says that Force equals mass times acceleration or F = ma

We get a = F/m

If we want the greatest acceleration or a, mass or m must be the lowest.

6 0
3 years ago
A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
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8 0
3 years ago
Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said
ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

7 0
2 years ago
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