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3 years ago

Which of the following are vector quantities?

Physics

2 answers:

Mazyrski [523]3 years ago

5 0

Answer:

displacement and acceleration

oksano4ka [1.4K]3 years ago

3 0

Answer:

Displacement and acceleration

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Which of the following statements about energy is true?

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Answer:ll. Kinetic energy can be transformed into Potential energy.

And, lll. Potential energy can be transformed into Kinetic energy

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If you were told an atom was an ion, you would know the atom must have a...

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An ion has a negative charge

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3 years ago

The distance between two successive maximaof

denpristay [2]

Answer:

v = 1.224 m/s

Explanation:

given,

distance between the two successive maxima = 1.70 m

number of crest = 8

time = 11 s

frequency is equal to number of cycle per secod

$f = \dfrac{8}{11}$

$f = 0.72\ Hz$

velocity of wave

v = f x λ

v = 0.72 x 1.70

v = 1.224 m/s

Hence, the wave speed is equal to v = 1.224 m/s

4 0

3 years ago

A gas was compressed to 30.0 mL at 1.5 atm from 65<br>mL. What was the original pressure?

astra-53 [7]

A gas as 30.0 Ml because pile of 1.4 add 1 that equals. To 1.5 and remove 10 so thebpresssure is 1399.93

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3 years ago

To what volume will a sample of gas expand if it is heated from 50.0°c and 2.33 l to 500.0°c?

Lena [83]

The volume of the gas at $500^{\circ} \text{C}$ is $\fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}$ .

Further Explanation:

Consider the pressure of the gas to be constant.

The change in the volume of the gas when the temperature of the gas is varied by keeping the pressure of the gas at a constant value is defined by the Charles' Law.

Concept:

According to the Charles law, the volume of the gas is directly proportional to the temperature of the gas at constant pressure.

The Charles' law can be stated as:

$\fbox{\begin\\V\propto T\\\end{minispace}}$

The above expression can we written as.

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Convert the temperature of the gas into kelvin.

$T=273+T^\circ\text{C}}}$

Here, T is the temperature in kelvin and $T^\circ\text{C}}}$ is the temperature in centigrade.

The initial temperature of the gas is $50^\circ\text{C}$ . The temperature of the gas in kelvin is.

$\begin{aligned}{T_1}&=273+50\\&=323\,{\text{K}}\\\end{aligned}$

The final temperature of the gas is $500^\circ\text{C}$ . The temperature in kelvin is.

$\begin{aligned}{T_2}&=273+500\\&=773\,{\text{K}}\\\end{aligned}$

Substitute the values of temperature and volume in the expression of the Charles' Law.

$\begin{aligned}{V_2}&=\frac{{{T_2}}}{{{T_1}}}{V_1}\\&=\frac{{773\,{\text{K}}}}{{323\,{\text{K}}}}\left({2.33\,{\text{L}}}\right)\\&=5.576\,{\text{L}}\\\end{aligned}$

Thus, the volume of the gas at $500^\circ\text{C}}$ will be $\fbox{\begin\ 5.576\,{\text{L}}\\\end{minispace}}$ .

Learn More:

1. Examples of wind and solar energy brainly.com/question/1062501

2. Stress developed in a wire brainly.com/question/12985068

Answer Details:

Grade: High school

Subject: Physics

Chapter: Gas law

Keywords:

Charles law, temperature, volume, initial, final, kelvin, centigrade, 50 C, 500 degree, 500 C, 50 degree, 2,33 L, gas expand, sample, heated.

7 0

3 years ago