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2 years ago

Which of the following are vector quantities?

Physics

2 answers:

Mazyrski [523]2 years ago

5 0

Answer:

displacement and acceleration

oksano4ka [1.4K]2 years ago

3 0

Answer:

Displacement and acceleration

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Water flowing through a cylindrical pipe suddenly comes to a section of the pipe where the diameter decreases to 86% of its prev

masha68 [24]

Answer:

The speed in the smaller section is $43.2\,\frac{m}{s}$

Explanation:

Assuming all the parts of the pipe are at the same height, we can use continuity equation for incompressible fluids:

$\Delta Q=0$ (1)

With Q the flux of water that is $Av$ with A the cross section area and v the velocity, so by (1):

$A_{2}v_{2}-A_{1}v_{1}=0$

subscript 2 is for the smaller section and 1 for the larger section, solving for $v_{2}$ :

$v_{2}=\frac{A_{1}v_{1}}{A_{2}}$ (2)

The cross section areas of the pipe are:

$A_{1}=\frac{\pi}{4}d_{1}^{2}$

$A_{2}=\frac{\pi}{4}d_{2}^{2}$

but the problem states that the diameter decreases 86% so $d_{2}=0.86d_{1}$ , using this on (2):

$v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\approx1.35v_{1}$

$v_{2}\approx(1.35)(32)\approx43.2\,\frac{m}{s}$

5 0

3 years ago

What is this object? Explain how it works and which one of Newton’s laws this represents.

lyudmila [28]

Answer:

the object is called Newton's cradle balance ball you can search it on Google

4 0

2 years ago

A stone is tied to a string and whirled at constant speed in a horizontal circle. The speed is then doubled without changing the

Tanya [424]

Answer:

Afterward the magnitude of the acceleration of the stone is four times as great

Explanation:

A stone tied to a string and whirled at a constant speed in a horizontal circle will have a centripetal acceleration given by

$a = \frac{v^{2} }{r}$

Where $a$ is the centripetal acceleration

$v$ is the speed

and $r$ is the radius of the circle

Here, the radius of the circle is the length of the string.

Now, from the question

The speed is then doubled without changing the length of the string,

Let the new speed be $v_{2}$ , that is

$v_{2} = 2v$

and without changing the length of the string means radius $r$ is constant.

To determine the magnitude of the acceleration of the stone afterwards,

Let the new acceleration be $a_{2}$ .

Then we can write that

$a_{2} = \frac{v_{2}^{2} }{r}$

From

$a = \frac{v^{2} }{r}$

$v = \sqrt{ar}$

Recall that

$v_{2} = 2v$

∴ $v_{2} = 2\sqrt{ar}$

Now, we will put the value of $v_{2}$ into

$a_{2} = \frac{v_{2}^{2} }{r}$

Then,

$a_{2} = \frac{(2\sqrt{ar}) ^{2} }{r}$

$a_{2} = \frac{4ar }{r}$

$a_{2} = 4a$

The new magnitude of the acceleration of the stone is four times the initial acceleration.

Hence,

Afterward the magnitude of the acceleration of the stone is four times as great

3 0

2 years ago

Define the term acceleration due to gravity

kifflom [539]

Answer

Acceleration

Acceleration Means rate of Change of velocity with respect to time.

acceleration due to gravity

when a body falls freely means no other force act on it except gravitational force that time velocity of object does not remains constant but it changes as it approaches towards the ground it means body get accelerated and this acceleration which is gained by the body due to gravitational force is called its acceleration due to gravity it is denoted by g. Acceleration due to gravity is different on different planet. SI unit of is m/s^2 . On earth its standard value is 9.80665m/s^2.

7 0

2 years ago

A 1-kg ball is thrown at 10 m/s straight upward. neglecting air resistance, the net force that acts on the ball when it is half

Marrrta [24]

Because of gravity it has 10N force downward

4 0

2 years ago

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