Complete the table of values for y=2x squared + x
1 answer:
Answer:
y=2x^2 + 2x - 3 x -2 -1 0 1 2
Step By Step Explanation:
The values can be find by plugging the x values in the equation which gives us the y value ,
x -2 -1 0 1 2
y 1 -3 -3 1 9
(b) Plot the points on the graph and join by a smooth curve.
(c) The line y=1 will be passing through 1 and parallel to x-axis.
(d) solve 2x^2 + 2x - 3 = 1
Subtract 1 from both the sides ,
2x^2 + 2x - 2 = 0
Factoring out the 2 from the equation ,
2(x^2 + x - 1) = 0
x^2 + x - 1 = 0
Apply the quadratic formula
x=(-1-sqrt(5))/2 and x = (-1+sqrt(5))/5
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Try this option:
x²+27=0;
Answer:
The function touches the damping factor
at x= and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)= and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
