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frosja888 [35]
3 years ago
12

A roller coaster car starts at a height of 90 M at Point a and is moving at a speed of 20 m per second on a later Hill at Point

C assuming friction does not affect the motion of the car what is its height at Point C
Physics
2 answers:
ankoles [38]3 years ago
7 0
Hi there!

The answer you are looking for.....



20.4 m!





Hope this helps you!

Have a great day!
valentina_108 [34]3 years ago
3 0
The answer is 20.4m in height. You can use the kinematics equation Vf^2=V0^2+2ad  Therefore we have solving for d or height, we get d=Vf^2/2g
(20m/s)^2/(2*9.8m/s^2)=20.4m
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For each of the following pairs of gas properties, describe the relationship between the properties, describe a simple system th
asambeis [7]

Answer:

For  each pair of properties of a gas, the relationships are (see the explanation for the description of the systems):

  1. (a) Volume and pressure: The relationship between them is inversely proportional.
  2. (b) Pressure and temperature: They have a directly proportional relationship.
  3. (c) Volume and temperature: They relationship is directly proportional.
  4. (d) Number of gas particles and pressure: The relationship is directly proportional between them.

Explanation:

1. Volume and pressure (temperature and amount of particles constant):

They have an inversely proportional relationship, because <em>if volume is reduced, the pressure increases, or if the volume increases, the pressure decreases</em>.

A simple system could be one similar to the one used by Boyle to test this relationship:

  • Seal the short extreme of a translucent J tube. It could be glass or plastic.
  • Put some water on it. As much as needed to have both sides of the tube filled.
  • Using a syringe, and a flexible small tube,inject a determined volume of air in the bottom in a way that the bubble is trapped in the seal side of the J tube.
  • Then if more water is added to the tube, it will increase the pressure (from the pressure definition is possible to in the trapped air, and is possible to measure the compression of the air bubble. The same is possible if using the syringe, and the flexible tube, some water is removed, and the increasing of volume could be observed.

2. Pressure and temperature (volume and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure would increase, also</em>.

A simple system to show this is two cans of soda.

  • The can is rigid, so the volume is always constant, and the amount of gas inside the soda is the same.
  • Put one can under the sun, and the other in the cooler.
  • After a while, take it out the can in the cooler, and open both cans.
  • The one that was under the sun will "explode", in other words, it will liberate a lot of foam of gas and soda, meaning that the pressure inside the can was high.
  • The one that was in te cooler, won't liberate any foam, meaning that the pressure was low.

3. Volume and temperature (pressure and amount of particles of the gas remains constant)

They have a directly proportional relationship, because <em>if temperature is reduced, the pressure decreases, or if the temperature increases, the pressure will increase, also</em>.

A simple system to show this is a party balloon.

  • Fill the party balloon with some air, not enough to be close to explode, but enough to have it of a medium size. Tie the filling hole of the balloon.
  • The air inside the balloon would be at the same pressure than the atmosphere around it, so always will be at this pressure, and the close hole ensure that it has always the same amount of air inside.
  • Now is possible to use some heat source, for example as a hair dryer to increase the temperature of the balloon and its contents. The size of the balloon will increase. Then using water is possible to cool it down and watch how its size decreases.

4. Number of gas particles and pressure (volume and temperature of gas remains constant)

They have a directly proportional relationship, because <em>if the amount of gas particles is reduced, the pressure decreases, or if quantity of gas particles increases, the pressure will increase, also</em>.

A simple system to show this would be a bicycle tire:

  • The tire is rigid, so its volume is essentially constant, and the temperature would remains the same if not moving or driving it.
  • Using a tire gauge, it is possible to know the manometric pressure inside the tire, that is the difference between the actual pressure inside the tire and the atmospheric pressure.
  • Then each time that using an air pump some air is injected in the tire, it si possible to check the pressure inside it using the gauge, and observe how is increasing.
  • Also, is possible to open the valve, to allow some air to escape, then use the gauge to observe how the pressure decreases.

7 0
3 years ago
A tennis ball travels the length of the court 24m in 0.5s. Find the average speed
AnnZ [28]

Answer: average speed of the ball would be 48 mph

Explanation:

because all you have to do is multiply 24 x .5 and that gives you your answer

5 0
3 years ago
Explain why it is important to identify a reference point for any description of motion.
Leya [2.2K]

A reference is critical because it determines how much motion has occurred. You can't determine how much an objected has moved if you don't know where it came from.

3 0
3 years ago
Read 2 more answers
In Scientific Notation, numbers are written in the form a x 10b . In this form, b is called the
ivann1987 [24]

Answer:

b is called the power of base 10.

Explanation:

In the scientific notation form  

a\,\,10^b

the exponent b is called the power of the base 10.

3 0
3 years ago
When an old lp turntable was revolving at 33.3 rpm, it was shut off and uniformly slowed down and stopped in 5.5 seconds. throug
velikii [3]
First, let's convert the initial angular speed from rpm (rev/min) into rad/s, keeping in mind that 1 rev = 2 \pi rad and 1 min=60 s:
\omega_i = 33  \frac{rev}{min}=33\frac{rev}{min} \cdot  \frac{2 \pi rad}{60 s}=3.45 rad/s

Now we can find the angular acceleration of the lp, keeping in mind that the final speed is zero:
\alpha =  \frac{\omega_f - \omega_i}{t}= \frac{0-3.45 rad/s}{5.5 s}=-0.63 rad/s^2
and the acceleration is negative because the LP is decelerating.

Now we can find the angle covered by the LP from the beginning to the end of its motion:
\theta (t)= \omega_i t + \frac{1}{2}\alpha t^2 = (3.45 rad/s)(5.5 s)+ \frac{1}{2}(-0.63 rad/s^2)(5.5 s)^2=
=9.45 rad

And finally, we can convert it into number of revolutions:
1 rev : 2 \pi rad = x: 9.55 rad
x= \frac{9.55}{2 \pi}= 1.52 rev
4 0
3 years ago
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