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iris [78.8K]
3 years ago
14

A box weighing 4.0 N is lifted 3.0 meters. How much work is done on the box?

Physics
1 answer:
Rashid [163]3 years ago
6 0

The answer is 12 J

because you have to multiply the two together. hope it helps


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If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be
Lynna [10]

Answer:

Explanation:

First of all, well calculate the spring constant k

K = 2Ei/x^2

Where Ei = initial work required

x = initial stretch length

k = 2×7/0.017^2 = 48443J/m^2

Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

EF = kx^2/2

48443 × 0.053^2/2 = 68J

Work done in stretching additional 3.6cm is equal to

68J-7J = 61J

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4 years ago
An electron is moving at a constant speed of 61 m/s on a circle of radius 3.8 m.
alexira [117]
Charge on electron is 1.6x10^-19 Coulombs.In uniform circular motion v = r omega. omega = v/r. omega= 61/3.8 radians per second - cycle is 2pi radians. (61/3.8)x2pi cycles per second. A charge circulation rate of  (61/3.8)x2pix1.6x10^-19 Coulombs/second, or Amps. Which is a pretty small value of a current. Usually there many more electrons moving much faster, I think.
7 0
3 years ago
What happens when a force exerted on an object causes the object to move?
stiks02 [169]

Answer:

Work is done on the object.

Explanation:

5 0
3 years ago
How did Archimedes measure the mass of the block of gold?
MA_775_DIABLO [31]
Archimedes found a piece of gold and a piece of silver with exactly the same mass. He dropped the gold  into a bowl filled to the brim with water and measured the volume of water that spilled out. Then he did the same thing with the piece of solver. Although both metals had the same mass, the silver gad a larger volume; therefore, it displaced more water than the gold did. That's because the silver was less dense than gold. Afterwards he applied the same method to the crown for the king he served who had got a new crown from a jeweler who gave it to him. Archimedes found a piece of pure gold that had the same mass as the crown. He placed the pure gold chuck and the crown in water, one at a time. The crown displaced more water the piece of gold. Therefore, its density was less than pure gold.  
5 0
3 years ago
Newton's law of universal gravitation is represented by f = g mm r2 where f is the gravitational force, m and m are masses, and
Sedbober [7]

Answer: {kg^{-1}}{s^{-2}}m^3

F=G \frac {mM}{R^2}

force has the SI units:

kg . ms^{-2}

SI unit of mass is kg and SI unit of distance is m.

we can bring gravitational constant on one side of the formula and rest all the other terms on right hand side

G= \frac {F}{mM}\times R^2=\frac{kg . ms^{-2}}{kg^2} \times m^2\\ = {kg^{-1}}{s^{-2}}m^3


6 0
4 years ago
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