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astraxan [27]
3 years ago
9

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is A. definitely les

s. B. often less. C. actually more D. the same.
Physics
2 answers:
pashok25 [27]3 years ago
8 0

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is

D. the same.

As per the rule, the amount of current in devices connected in series is equal. here in the given situation , the wire is in series with the filament. that is the reason that the current in filament and wire is same.

hence the correct choice is D)

nevsk [136]3 years ago
5 0

Answer:

D. the same.

Explanation:

The amount od current that flows through the filament of a lamp is actually the same that it would be compared with the amount of current that is flowing though the connecting wire, unless the lamp has a kind of resitor where it downgrades the amount of current befor it passes through the filament of the lamp, the currecnt should be the same.

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Answer:

b

Explanation:

i just answered it and the correct answer is b

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Chewy travels an average of 22 mph, how many hours does it take him to cover a 110 mike course?
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That would be 110/22, which is 5 hours
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A kg object has 400 j of potential energy. Find how high off the groumd the object is
blondinia [14]
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g = 10m/s^2
m = A kg
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6 0
3 years ago
This experiment, you compare several unknown powders to known powders. What is the name given to all of the known materials used
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5 0
3 years ago
Read 2 more answers
A light-weight potter’s wheel, having a moment of inertia of 24 kg m2 is spinning freely at 40.0 rpm. The potter drops a small b
mixer [17]

Answer:

m=4.03 kg

Explanation:

Given that

r= 1.2 m

I=24 kg.m²

N₁ = 40 rpm

\omega_1=\dfrac{2\pi N_1}{60}\ rad/s

\omega_1=\dfrac{2\pi \times 40}{60}\ rad/s

ω₁= 4.1 rad/s

N₂=32 rpm

\omega_2=\dfrac{2\pi \times 32}{60}\ rad/s

ω₂ = 3.3 rad/s

Lets take mass of clay = m kg

Initial angular momentum L₁

L₁ =  Iω₁    

Final linear momentum L₂

L₂=  I₂ ω₂

I₂ = I + m r²

The is no any external torque that is why angular momentum will be conserve

L₁ = L₂

Iω₁  =  I₂ ω₂

Iω₁  =  ( I + m r²) ω₂

Now by putting the all values

Iω₁   =  ( I + m r²) ω₂

24 x 4.1 = (24 + m x 1.2²) x 3.3

24 x 4.1 = (24 + 1.44 m) x 3.3

29.81 = 24 + 1.44 m

1.44 m = 5.81

m=4.03 kg

7 0
3 years ago
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