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vesna_86 [32]
3 years ago
6

An automobile tire having a temperature of −1.5 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 26 lb/in2 . What

would be the gauge pressure in the tire when its temperature rises to 40◦C? For simplicity, assume that the volume of the tire remains constant, that the air does not leak out and that the atmospheric pressure remains constant at 14.7 lb/in2 . Answer in units of lb/in2 .
Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:32.22\ lb/in^2

Explanation:

Given

Temperature on the hot day T_i=-1.5^{\circ} C\approx 271.5\ K

Gauge Pressure P_i=26\ lb/in^2

When Temperature rises to T_f=40^{\circ}C\approx 313\ K on a hot day then

absolute pressure  is let say P_f

Using ideal gas equation we can write

\Rightarrow \frac{PV}{T}=constant

as volume is constant therefore

\Rightarrow \frac{P}{T}=constant

\Rightarrow \frac{26+14.7}{271.5}=\frac{P_f}{313}

\Rightarrow P_f=46.92\ lb/in^2

Gauge Pressure is given by

\Rightarrow 46.92-14.7=32.22\ lb/in^2

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Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
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Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

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Area of the rectangle = 2.536mm * 1.41mm

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Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

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An electron is initially at rest in a uniform electric field having a strength of 1.85 × 106 V/m. It is then released and accele
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W = 462.5 keV

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W = 462.5 keV

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