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Luden [163]
3 years ago
14

A negatively charged particle is moving to the right, directly above a wire having a current flowing to the right, as shown belo

w. In which direction is the magnetic force exerted on the particle?Answera. out of the pageb. into the pagec. upwardd. downwarde. The magnetic force is zero since the velocity is parallel to the current.
Physics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

Explanation:

As the current in the ire is towards right and the charge particle is above the wire, the direction of magnetic field due to the current carrying wire is perpendicularly outwards to the plane of paper. It is calculated by the Maxwell's right hand thumb rule. Now by using the Fleming's left hand rule, the direction of force is upwards.

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The imaginary point in the sky directly above the North Pole is _____.
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C) A sample of substance of volume 10 cm3 was brought back to Earth from the Moon.
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3 years ago
A beam of light strikes a sheet of glass at an angle of 57.0°. with the normal in air. You observe that red light makes an angle
Lena [83]

Answer:

a) Red: 1.34

Violet: 1.40

b) Red: 2.23\times10^8\frac{m}{s}

Violet: 2.14\times10^8\frac{m}{s}

Explanation:

a) We should use Snell's law to find the index of refraction:

n_{1}sin\theta_{i}=n_{2}sin\theta_{t}

with n1 the index of refraction of air, n2 the index of refraction of the glass, θi the angle of the incident ray respects the normal an θt the angle between the refracted ray an the normal. It's common to approximate n1=1

solving n2 for red light:

\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}

n_2=\frac{sin57.0}{sin38.1}= 1.34

solving n2 for violet light:

\frac{sin\theta_{i}}{sin\theta_{t}}=n_{2}

n_2=\frac{sin57.0}{sin36.7}= 1.40

b) Index of refraction on a medium is defined as the ratio between the velocity of electromagnetic waves on vacuum (velocity of light c) and the velocity in medium (v):

n_2=\frac{c}{v}

solving v for red:

v=\frac{c}{n_2}=\frac{3\times10^8}{1.34}=2.23\times10^8\frac{m}{s}

solving v for violet

v=\frac{c}{n_2}=\frac{3\times10^8}{1.40}=2.14\times10^8\frac{m}{s}

8 0
3 years ago
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