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Luden [163]
3 years ago
14

A negatively charged particle is moving to the right, directly above a wire having a current flowing to the right, as shown belo

w. In which direction is the magnetic force exerted on the particle?Answera. out of the pageb. into the pagec. upwardd. downwarde. The magnetic force is zero since the velocity is parallel to the current.
Physics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

Explanation:

As the current in the ire is towards right and the charge particle is above the wire, the direction of magnetic field due to the current carrying wire is perpendicularly outwards to the plane of paper. It is calculated by the Maxwell's right hand thumb rule. Now by using the Fleming's left hand rule, the direction of force is upwards.

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Eukaryotic that can reproduce sexually contain two types of cells
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7 0
3 years ago
On a spinning ride at the fair, it is inertia that keeps you moving in a circle. true or false​
lions [1.4K]

False, the inertia does not keep us moving in a circle on a spinning ride at the fair.

Answer: Option B

<u>Explanation: </u>

Inertia is the resisting force of any object which resists in change in their state. If an object is moving the inertia will act in opposing direction to the force acting on the object stopping its motion.

Similarly, if an object resembles at rest, then the inertia will be acting against the force tending to move that stationary object. So, on a spinning ride at fair, when a person sits there, the inertia acting on the person will prevent the person to falling down from the fair and not in moving in a circle.

6 0
3 years ago
The work done on a box is 532 joules. The force applied to the box was 48 N. What was the displacement of the box? *
Semenov [28]

Explanation:

Work = force × displacement

532 J = 48 N × d

d ≈ 11 m

8 0
3 years ago
A charged particle moves in a circular path in a uniform magnetic field.Which of the following would increase the period of the
Bond [772]

Answer:

Increasing its charge

Increasing the field strength

Explanation:

For a charged particle moving in a circular path in a uniform magnetic field, the centripetal force is provided by the magnetic force, so we can write:

qvB = m\frac{v^2}{r}

where

q is the charge

v is the velocity

B is the magnetic field

m is the mass

r is the radius of the orbit

The period of the motion is

T=\frac{2\pi r}{v}

Re-arranging for r

r=\frac{Tv}{2\pi}

And substituting into the previous equation

qvB = m \frac{Tv^3}{2\pi}

Solving for T,

T=\frac{2\pi q B}{m v^2}

So we see that the period is:

- proportional to the charge and the magnetic field

- inversely proportional to the mass and the square of the speed

So the following will increase the period of the particle's motion:

Increasing its charge

Increasing the field strength

4 0
3 years ago
A certain computer chip that has dimensions of 3.67 cm and 2.93 cm contains 3.5 million transistors. If the transistors are squa
Evgesh-ka [11]

Answer:

1.56 × 10^-3 cm.

Explanation:

So, we are given the following parameters from the question above;

Length = 3.67 cm, breadth = 2.93 cm, and the number of embedded transistors = 3.5 million.

Step one: find the area of the computer chip.

Therefore, Area = Length × breadth.

Area = 3.67 cm × 2.93 cm.

Area of the computer chip = 10.7531 cm^2. = 10.75 cm^2.

Step two: find the area of one transistor

The area of one transistor is; (area of the computer chip) ÷ (number of embedded transistors).

Hence;

The area of one transistor= 10.7531/4.4 × 10^6.

The area of one transistor= 2.44 × 10^-6 cm^2.

=> Note that We have our transistors as square, therefore;

The maximum dimension = √ (2.44 × 10^-6) cm^2.

The maximum dimension= 1.56 × 10^-3 cm.

7 0
3 years ago
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