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Luden [163]
3 years ago
14

A negatively charged particle is moving to the right, directly above a wire having a current flowing to the right, as shown belo

w. In which direction is the magnetic force exerted on the particle?Answera. out of the pageb. into the pagec. upwardd. downwarde. The magnetic force is zero since the velocity is parallel to the current.
Physics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

Explanation:

As the current in the ire is towards right and the charge particle is above the wire, the direction of magnetic field due to the current carrying wire is perpendicularly outwards to the plane of paper. It is calculated by the Maxwell's right hand thumb rule. Now by using the Fleming's left hand rule, the direction of force is upwards.

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Use newton's law to explain the vertical acceleration of a projectile
NISA [10]

Answer:

Explained below

Explanation:

Newton's first law of motion: This law states that an object will remain at rest or continue in constant motion except it's acted upon by an external force. In projectile motion, the horizontal component of velocity will remain unchanged because we ignore air resistance since no force is acting in that horizontal direction.

Newton's second law of motion: This law states that force is the product of mass and acceleration. In projectile the force acts downwards, thus f = mg.

But g = a since internal forces will cancel out.

Thus, F = ma

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3 years ago
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Velocity: You leave on a 549-mi trip in order to attend a meeting that will start 10.8 h after you begin your trip. Along the wa
rewona [7]

Answer:

1.55 h

Explanation:

Let the time to spend over dinner be t.

Since I need to spend 10.8 h for the whole trip, then I have 10.8 - t hours left to drive.

Speed = distance/time

v = \dfrac{d}{10.8-t}

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The distance is 549 and maximum speed is 65 mi/h.

549 = 65(10.8 - t)

10.8-t = 8.45

t = 10.8 - 8.45 = 1.55 \text{ h}

5 0
3 years ago
Isotopes of the same element vary in the number of ____ present in the nucleus A.neutrons
I am Lyosha [343]
A. Neutrons.
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5 0
3 years ago
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If you mark off a beginning time and ending time on the graph,
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