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MrRa [10]
3 years ago
5

Reaction E0

Chemistry
1 answer:
kherson [118]3 years ago
8 0
Yes because you should always be positive
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How many atoms of hydrogen are represented in 2CH3CH2O?
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5 you can tell because it comes after the letter.
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A constant volume of oxygen is heated from 100°C to 155°C. The
dybincka [34]

Answer:

= 3.56 atm

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure and Charles law states the volume of a given mass of gas is directly proportional to the temperature.

P1/T1 = P2/T2

P1 = 3.1 atm, T1 = 100'C = 100+273 = 373K

T2 = 155'C = 155 + 273 = 428K

3.1/ 373 = P2 / 428

Cross multiply

373 × P2 = 3.1 × 428

373×P2 = 1326.8

Divide both sides by 373

P2 = 1326.8 ÷ 373

P2 = 3.56 atm

I hope this was helpful, please mark as brainliest

3 0
3 years ago
Identify and describe the three ways that mutations affect organisms?
Soloha48 [4]

Answer:

The ways that mutation can affect an organism include:

Changing the physical characteristics of the organism.

It can impact the way that the DNA is able to code the genetic information.

Also, mutation can lead to the death of an organism.

What is mutation?

Mutation simply means a change in the DNA sequence of an organism. It can result from DNA copying mistakes that were made during the cell division.

Mutation can affect an organism as it changes the phenotype of the organism. It can also impact the way that the DNA is able to code the genetic information and lead to the death of an organism.

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Colligative properties depend upon the ____.
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The answer is G. choices b and c only
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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
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