No because u never know what will happen or what mother nature is thinking of
I'm not sure, i had this same question, and it doesn't make any logical sense because
A centimeter is a centimeter but in the video apparently not... for example in the video it showed the notebook as 40cm for one and the next one shows it as 14.4 cm it stayed as cm both times the size of the ruler should not change that one ruler was by 10cm the other was by 1 cm and it showed 2 completely different numbers
so therefore it doesn't make any logical sense
here was my measurements from the little video it had
try getting ahold of the teacher or whoever gave you the question its all you really can do...
hope this helped somewhat even through it probably didn't...
Answer:
-370.1 kJ/mol CpA = 84.5 J/(mol-K) CpB = 137 J/(mol-K) Cpc = 170 J/(mol-K) CpD = 75 J/(mol-K) To = 303 K FAo = 10 mol/min FBo = 30 mol/min v = 1000 L/min CAo =0.01 mol/L
Explanation:
The nitration of aromatic compounds is a highly exothetion that generally uses catalysts that tend to be corrosive (e.g., HNO3 /H2SO4 ). A less corrosive employs N2 O5 as the nitrating agent as illustrated below: If this reaction is conducted in an adiabatic CSTR, what is the reactor volume and space time necessary to achieve 35 percent conversion of N2O5? The reaction rate is first order in A and second order in B. Data: HRX = -370.1 kJ/mol CpA = 84.5 J/(mol-K) CpB = 137 J/(mol-K) Cpc = 170 J/(mol-K) CpD = 75 J/(mol-K) To = 303 K FAo = 10 mol/min FBo = 30 mol/min v = 1000 L/min CAo =0.01 mol/L
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rmic
Answer: gases
(has bubbles in the rock)
Explanation:
The equilibrium constant of the reaction =
Initial concentration of HI = 0.311 M
After addition 0.174 mol of HI(g)
Concentration of HI added =
New concentration of HI = 0.311 M + 0.174 M = 0.485 M
Initial concentration:
0.311 M
At equilibrium:
(0.485 M - x)
Equilibrium concentrations: