The volume occupied by 0.102 mole of the helium gas is 2.69 L
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Number of mole (n) = 0.102 moles
- Pressure (P) = 0.95 atm
- Temperature (T) = 305 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) =?
<h3>How to determine the volume </h3>
The volume of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both sides by P
V = nRT / P
V = (0.102 × 0.0821 × 305) / 0.95
V = 2.69 L
Thus, the volume of the gas is 2.69 L
Learn more about ideal gas equation:
brainly.com/question/4147359
#SPJ1
Hey there!
C = m
------
V
50.0 mg/mL = mass
---------------
425 mL
mass = 50.0 * 425
mass => 21250 mg
Over here you have to use the formula: <span>P1/T1= P2/T2
P1= 7.58
T1= 639
P2= ?
T2= 311
</span><span>7.58/639 = ?/311
</span>= 3.689 kPa
Answer:
C) There are fewer particles in the balloons than were in the cylinder.
Explanation:
Hope this helps good luck!- Angel
Answer: 5.06g/mL
Explanation: 14.1÷.737=19.131614654
19.131614654/3.78= 5.0612
