Answer:
2.46 × 10²⁵ atoms H
Explanation:
Avagadro's Number: 6.022 × 10²³
Step 1: Find formulas
Hydrogen - H
Ammonium Sulfide - (NH₄)₂S
Step 2: Use Dimensional Analysis
=
Step 3: Simplify
We have 3 sig figs.
2.45616 × 10²⁵ atoms H ≈ 2.46 × 10²⁵ atoms H
Answer:
Percent yield = 57.7 %Explanation:
Answer:
Percent yield = 94.5%
Theoretical yield = 26.89 g
Explanation:
Given data:
Mass of copper = 12.5 g
Mass of copper chloride produced = 25.4 g
Theoretical yield = ?
Percent yield = ?
Solution:
Cu + Cl₂ → CuCl₂
Number of moles of Copper:
Number of moles = mass/ molar mass
Number of moles = 12.5 g/ 63.55 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of copper with copper chloride.
Cu : CuCl₂
1 : 1
0.2 : 0.2
Theoretical yield:
Mass of copper chloride:
Mass = Number of moles × molar mass
Mass = 0.2 mol × 134.45 g/mol
Mass = 26.89 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 25.4 g/26.89 g × 100
Percent yield = 94.5%
CH₂O = C + 2.H + O
= 12.01 + 2 x 1.008 + 16
= 30.026 amu = 30.026 g/mol
Answer:
- Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
- Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
- As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Explanation:
The <em>electron configuration</em> indicates the way the electrons of an atom or ion are structured.<u> In the case of cations</u>, by knowing the electronic configuration of the atom (which is neutral), we can find out the cations' configuration by substracting <em>n</em> outermost electrons, where <em>n</em> is the charge of the cation.
Mg⁰ ⇒ [Ne] 3s² = 1s² 2s² 2p⁶ 3s². Thus
Mg⁺² ⇒ [Ne] = 1s² 2s² 2p⁶.
In a similar fashion, the answers are:
Sn²⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰
K⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶
Al³⁺ ⇒ 1s² 2s² 2p⁶
Ti⁺ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 4f¹⁴ 6s² 5d¹⁰
As⁺³ ⇒ 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
