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3 years ago

12

What is the measure of speed in a certain direction

1 answer:

Marianna [84]3 years ago

4 0

It is the speed of that direction

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In a solution, the substance that does the dissolving is called:

snow_tiger [21]

C. Solvent

A solvent is a substance that can be dissolved. A solute is a substance dissolve in a solvent. Saturated is something where it holds as much of a substance as it can. Precipitate means it's evaporated.

Hope This Helped! Good Luck!

7 0

3 years ago

A mass attached to a spring oscillates and completes 53 full cycles in 28 s. What is the time period (in s) and frequency (in Hz

ivann1987 [24]

Explanation:

It is given that, a mass attached to a spring oscillates and completes 53 full cycles in 28 s. Frequency of the system is given by the number of oscillations or vibrations per second. Here, the frequency of this system is given by :

$f=\dfrac{no\ of\ oscillations}{time}$

$f=\dfrac{53}{28}$

f = 1.89 Hertz

The relationship between the frequency and the time period of the spring is inverse i.e.

$T=\dfrac{1}{f}$

$T=\dfrac{1}{1.89\ Hz}$

T = 0.52 seconds

Hence, this is the required solution.

5 0

4 years ago

A car accelerates uniformly in a straight line

kotegsom [21]

The car covers a distance <em>d</em> after time <em>t</em> of

<em>d</em> = (2.8 m/s²) <em>t</em>²

Solve for <em>t</em> when <em>d</em> = 69 m:

69 m = (2.8 m/s²) <em>t</em>²

<em>t</em>² = (69 m) / (2.8 m/s²)

<em>t</em> ≈ 4.96 s

6 0

4 years ago

a solid weighs 18.36N on the surface of the moon. The force of gravity on the moon is 1.7Nkg-1. Determine the mass of the solid

Karo-lina-s [1.5K]

Answer:

mass of the solid is 10.8kg

Explanation:

Weight of the solid=w=18.36N

Force of gravity on the surface of the moon=g=1.71Nkg^-1

Mass of the solid on the moon=m=?

as we know that

weight=mass×force of gravity

here we have to find the mass

$\frac{weight}{force of gravity}$ =mass

mass= $\frac{18.36N}{1.7Nkg^-1}$

Mass of the solid=10.8kg

i hope it will help you

7 0

3 years ago

A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the

BartSMP [9]

Answer:

$r=1.14m$

Explanation:

$\theta$ is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

$F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB$

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

$F_m=F_c\\qvB=F_c(1)$

$F_c$ is the centripetal force and is defined as:

$F_c=m\frac{v^2}{r}$

Here $v$ is the proton's speed and $r$ is the radius of the circular motion. Replacing this in (1) and solving for r:

$qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}$

Recall that 1 J is equal to $6.242*10^{12}MeV$ , so:

$4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J$

We can calculate $v$ from the kinetic energy of the proton:

$K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}$

Finally, we calculate the radius of the proton path:

$r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m$

8 0

4 years ago