Answer:
The slope-intercept equation is:
![y=\frac{3}{2}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B1)
Step-by-step explanation:
Given the equation
![y-4=-\frac{2}{3}\left(x-6\right)](https://tex.z-dn.net/?f=y-4%3D-%5Cfrac%7B2%7D%7B3%7D%5Cleft%28x-6%5Cright%29)
comparing it with the point-slope form of the line equation
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
where m is the slope
- so the slope of the line is -2/3.
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
The slope of the perpendicular line will be: 3/2
The point-slope form of the equation of the perpendicular line that goes through (-2, -2) is:
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
![y-\left(-2\right)=\frac{3}{2}\left(x-\left(-2\right)\right)](https://tex.z-dn.net/?f=y-%5Cleft%28-2%5Cright%29%3D%5Cfrac%7B3%7D%7B2%7D%5Cleft%28x-%5Cleft%28-2%5Cright%29%5Cright%29)
![y+2=\frac{3}{2}\left(x+2\right)](https://tex.z-dn.net/?f=y%2B2%3D%5Cfrac%7B3%7D%7B2%7D%5Cleft%28x%2B2%5Cright%29)
writing the line equation in the slope-intercept form
![y+2=\frac{3}{2}\left(x+2\right)](https://tex.z-dn.net/?f=y%2B2%3D%5Cfrac%7B3%7D%7B2%7D%5Cleft%28x%2B2%5Cright%29)
subtract 2 from both sides
![y+2-2=\frac{3}{2}\left(x+2\right)-2](https://tex.z-dn.net/?f=y%2B2-2%3D%5Cfrac%7B3%7D%7B2%7D%5Cleft%28x%2B2%5Cright%29-2)
![y=\frac{3}{2}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B1)
Thus, the slope-intercept equation is:
![y=\frac{3}{2}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B1)
Here,
As the slope-intercept form is
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
where m is the slope and b is the y-intercept
so
![y=\frac{3}{2}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B1)
m=3/2
b = y-intercept = 1
Therefore, the slope-intercept equation is:
![y=\frac{3}{2}x+1](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B1)
Answer:
(0;-9)
Step-by-step explanation:
1. P(6,1)-P(3,5)=(6,1)-(3,5)=(3;-4)
2.(-3;-5)+(3;-4)=(0;-9)
The answer is C 20 5 term ninth of the sequence
Answer:
Part A)
This quadratic expression can be factored by using the difference of squares pattern.
Part B) (5x+y) and (5x-y)
Step-by-step explanation:
Given:
25x^2-y^2
above polynomial can be factorize by using difference of squares formula
a2-b2=(a+b)(a-b)
25x^2-y^2= (5x-y)(5x+y)
so for part A)
correct option is This quadratic expression can be factored by using the difference of squares pattern.
Part B)
As factored above in part A,
the factors of given polynomial 25x^2-y^2 are (5x+y)(5x-y)
so for part B) correct options are (5x+y) and (5x-y) !